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Luden [163]
3 years ago
15

What is the relationship between the strength of a bond (single vs double vs triple) and its wave-number on an IR spectrum? As t

he bond strength increases the wave number increases. As the bond strength increases the wave number decreases. As the bond strength decreases the wave number increases. Wave number is highest for double bonds and lowest for single and triple bonds. There is no relationship.
Physics
1 answer:
Elanso [62]3 years ago
8 0

<u>Explanation</u>

  • The relationship between the strength of a bond (single vs double vs triple) and its wave-number on an IR spectrum as the bond strength increases the wave number increases.

                STRENGTH OF BONDS TRIPLE>DOUBLE>SINGLE

                WAVE NUMBER SINGLE>DOUBLE>TRIPLE

  • wave number for single bond is greatest because it has greatest bond frequency among the three( more the frequency greater is the wave number).

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A 60 W light bulb is powered by a connection to a wall outlet with 120 V across the plug terminals. a) What is the current passi
Oxana [17]

Answer:

The current through the resistor is 0.5 A

Explanation:

Given;

power of the light bulb = 60 W

voltage in the wall outlet across the plug terminals = 120 V

power of the light bulb is the product of voltage in the wall outlet across the plug terminals and the current passing through the resistor.

power = voltage x current

Current = \frac{power}{voltage} = \frac{60}{120} = 0.5 A

Therefore, for a  60 W light bulb powered by a connection to a wall outlet with 120 V across the plug terminals, the current passing through the resistor is 0.5 A

7 0
3 years ago
Read 2 more answers
A 4.10 g bullet moving at 837 m/s strikes a 820 g wooden block at rest on a frictionless surface. The bullet emerges, traveling
atroni [7]

Answer:

(a) 1.85 m/s

(b) 4.1 m/s

Explanation:

Data

  • bullet mass, Mb = 4.10 g
  • initial bullet velocity, Vbi = 837 m/s
  • wooden block mass, Mw = 820 g
  • initial wooden block  velocity, Vwi = 0 m/s
  • final bullet velocity, Vbf = 467 m/s

(a) From the conservation of momentum:

Mb*Vbi + Mw*Vwi = Mb*Vbf + Mw*Vwf

Mb*(Vbi - Vbf)/Mw = Vwf

4.1*(837 - 467)/820 = Vwf

Vwf = 1.85 m/s

(b) The speed of the center of mass speed is calculated as follows:

V = Mb/(Mb + Mw) * Vbi

V = 4.1/(4.1 + 820) * 837

V = 4.1 m/s

6 0
3 years ago
 An ultrasound pulse used in medical imaging has a frequency of 5 MHz and a pulse width of 0.5 us. Ap- proximately how many osci
podryga [215]

At the frequency of 5 MHz, the period of the oscillations is 1/5meg. That's a period of 1/5 microsecond.

There are 5 full cycles in one full microsecond, and there are 2.5 full cycles in a 0.5 us pulse.

You'll have to decide for yourself how damped a pulse of 2.5 cycles is, because the parameters of the definition are corrupted in the question.

4 0
2 years ago
Name two appliance that use electromagnet.
Bess [88]

Answer:

Electromagnets are very widely used in electric and electromechanical devices, including:

Motors and generators.

Transformers.

Relays.

Electric bells and buzzers.

Loudspeakers and headphones.

Actuators such as valves.

Magnetic recording and data storage equipment: tape recorders, VCRs, hard disks.

6 0
2 years ago
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An unknown solid weighs 31.6 n. when submerged in water, its apparent weight is 19.8 n. what is the specific gravity of the unkn
KATRIN_1 [288]

specific gravity of the unknown sample = 2.68

Explanation:

True weight of solid=31.6 N

Apparent weight=19.8 N

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Loss in weight= weight of the liquid displaced

so weight of water displaced= 11.8 N

now specific gravity= weight of object/ weight of liquid displaced

specific gravity= 31.6/11.8

specific gravity= 2.68

6 0
3 years ago
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