Answer:
Distance, d = 0.1 m
It is given that,
Initial velocity of meson,
Finally, the meson is coming to rest v = 0
Acceleration of the meson, (opposite to initial velocity)
Using third equation of motion as :
s is the distance the meson travelled before coming to rest.
So,
s = 0.1 m
The meson will cover the distance of 0.1 m before coming to rest. Hence, this is the required solution.
The net force required to accelerate a car is 6000 N.
Force is defined as the product of the mass and acceleration of the body. Force is used to changing the velocity that is to accelerate an object or a body of a particular mass. The unit of Force is Newton or kg m/s^2.
The formula used to calculate the net force is :
F = ma
where, F = Force
m = mass = 2000 kg
a = acceleration = 3.00 m/s^2
∴ F = 2000*3
F = 6000 N
Thus, to accelerate the car at 3.00 m/s^2 of mass 2000 kg net force required is 6000 N.
To learn more about force,
brainly.com/question/1046166
Answer:
took longer to complete one oscillation, that means its PERIOD increased, and the distance between the peaks of the graph would be longer.
line would be less. the period of oscillation would have any effect on the graph
The correct answer for the question that is being presented above is this one: "c. transition state stage." During the transition state stage, the reaction of the atoms have the highest energy. It is also <span>during the formation of the activated complex in the middle of the experiment.</span>
