-10p - (1-2p)
(Multiply (1-2p) by -1)
-10p - 1 + 2p
(Combine like terms)
-8p - 1
ANSWER: -8p - 1
Answer:
A
Step-by-step explanation:
A) The signs of the first derivative (g') tell you the graph increases as you go left from x=4 and as you go right from x=-2. Since g(4) < g(-2), one absolute extreme is (4, g(4)) = (4, 1).
The sign of the first derivative changes at x=0, at which point the slope is undefined (the curve is vertical). The curve approaches +∞ at x=0 both from the left and from the right, so the other absolute extreme is (0, +∞).
b) The second derivative (g'') changes sign at x=2, so there is a point of inflection there.
c) There is a vertical asymptote at x=0 and a flat spot at x=2. The curve goes through the points (-2, 5) and (4, 1), is increasing to the left of x=0 and non-increasing to the right of x=0. The curve is concave upward on [-2, 0) and (0, 2) and concave downward on (2, 4]. A possible graph is shown, along with the first and second derivatives.
The correct answer is: [A]: " 4x³ + x² − 11x + 15 " .
_______________________________________________________
<u>Note</u>:
_______________________________________________________
(6x³ − 4x + 5) − (2x³ − x² + 7x − 10) ;
= (6x³ − 4x + 5) − 1(2x³ − x² + 7x − 10) ;
_________________________________________
Examine the following portion of the expression:
_________________________________________
" − 1(2x³ − x² + 7x − 10) " ;
= (-1 * 2x³) − (-1 * x²) + (-1 * 7x) − (-1 * 10) ;
= (-2x³) − (-1x²) + (-7x) − (-10) ;
= (-2x³) + 1x² − 7x + 10 ;
= " − 2x³ + 1x² − 7x + 10 " ;
Now, bring down the other part:
6x³ − 4x + 5 − 2x³ + 1x² − 7x + 10 ;
Combine the "like terms" :
6x³ − 2x³ = + 4x³ ;
− 4x − 7x = − 11x ;
+ 5 + 10 = + 15 ;
and bring down the:
+ 1x² ( which equals: " x² ") ;
____________________________________________________
And rewrite:
____________________________________________________
→ " 4x³ + x² − 11x + 15 " ;
→ which is: Answer choice: [A]: " 4x³ + x² − 11x + 15 " .
____________________________________________________