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3 years ago

11

Jessica took a mylar balloon outside on a very cold day. As she waited for the bus the balloon began to shrink. What is the best

explanation of this? A) As the particles became cooler, they lost energy and moved less, resulting in less pressure on the balloon. B) As the particles became cooler, they gained energy and moved less, resulting in less pressure on the balloon. C) As the particles became cooler, they lost energy and moved less, resulting in more pressure on the balloon. D) As the particles became cooler, they gained energy and moved less, resulting in more pressure on the balloon.

2 answers:

Reil [10]3 years ago

8 0

A as the particles became cooler they lost energy and moved less resulting in less pressure on the balloon

marta [7]3 years ago

6 0

Answer: A)

Explanation:

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Two small conducting point charges, separated by 0.4 m, carry a total charge of 200 C. They repel one another with a force of 12

Lunna [17]

Answer:

200 C

Explanation:

Let C1 and C2 be their charges. According to Coulomb's law

$F_C = k\frac{C_1C_2}{R^2}$

where k = $8.99\times10^9 nm^2/C^2$ is the constant, R = 0.4m is the distance between them, F = 120 N is their resulting charge force

$120 = 8.99\times10^9\frac{C_1C_2}{0.4^2}$

$C_1C_2 = \frac{120*0.4^2}{8.99\times10^9} = 2.13\times10^{-9}$

Since their total charge is 200C:

$C_1 + C_2 = 200$ or $C_1 = 200 - C_2$

We can substitute the above equation

$C_1C_2 = (200 - C_2)C_2 = 2.13\times10^{-9}$

$-C_2^2 +200C_2 - 2.13\times10^{-9} = 0$

$C= \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

$C= \frac{-200\pm \sqrt{(200)^2 - 4*(-1)*(-0.00000000213)}}{2*(-1)}$

$C= \frac{-200\pm200}{-2}$

$C = 1.06 \times 10^{-11}$ or $C \approx 200$

So the larger charge is C = 200 C

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3 years ago

How much energy is needed to heat and melt 3.0 kg of copper initially at 83°C?

Ne4ueva [31]

As we know that in order to melt the copper we need to take the temperature of copper to its melting point

So here heat required to raise the temperature of copper is given as

$Q = ms\Delta T$

We know that

melting temperature of copper = 1085 degree C

Specific heat capacity of copper = 385 J/kg C

now we have

$Q = 3(385)(1085 - 83)$

$Q = 1157310 J$

$Q = 1157.3 kJ$

now in order to melt the copper we know the heat required is

$Q = mL$

here we know that

L = 205 kJ/kg

now from above formula

$Q = 3(205) kJ$

$Q = 615 kJ$

now total heat required will be

$Q = 1157.3 kJ + 615 kJ$

$Q = 1772.3 kJ$

As we know that

$1 Cal = 4.18 kJ$

now we have

$Q = \frac{1772.3}{4.18} = 430 KCal$

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3 years ago

you are standing on top of a 344 m tall building. A drone operated by your friend is headed straight down, at a speed of 37.0 m/

Kazeer [188]

Answer:

v = 74.0m/s

Explanation:

Look at the photo.

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3 years ago

An arrow is shot upward from the roof of a building 75 m high with an initial speed of 40 m/s. If g = 10 m/s2 , what total dista

Elenna [48]

Answer:

60m

Explanation:

According to one of the equation of motions, v² = u²+2as where;

S is the distance

u is the initial velocity

v is the final velocity

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Since the arrow is shot upwards, the body will experience a negative acceleration due to gravity i.e a = -g

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Given u = 40m/s, g = 10m/s², S = 75m

Substituting to get the final velocity of the arrow we will have;

v² = 40²-2(10)(75)

v² = 1600 - 1500

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v = √100

v = 10m/s

Total distance traveled is speed of the object × time taken

Total distance traveled = 10 × 6

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The arrow has therefore traveled 60m after 6seconds

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