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anygoal [31]
3 years ago
11

Jessica took a mylar balloon outside on a very cold day. As she waited for the bus the balloon began to shrink. What is the best

explanation of this? A) As the particles became cooler, they lost energy and moved less, resulting in less pressure on the balloon. B) As the particles became cooler, they gained energy and moved less, resulting in less pressure on the balloon. C) As the particles became cooler, they lost energy and moved less, resulting in more pressure on the balloon. D) As the particles became cooler, they gained energy and moved less, resulting in more pressure on the balloon.
Physics
2 answers:
Reil [10]3 years ago
8 0
A as the particles became cooler they lost energy and moved less resulting in less pressure on the balloon
marta [7]3 years ago
6 0

Answer:    A)

Explanation:

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A climber pulls herself 8 meters upwards with a force of 150 Newtons. If it takes her 16 seconds to cover the 8 meters, how much
mr Goodwill [35]

Answer:

 P = 75 W

Explanation:

given,

Distance, L = 8 m

Force,F = 150 N

Time, t = 16 s

Work by the climber

Work done = Force x displacement

W = F. L

W = 150 x 8

W = 1200 J

We know,

Power =\dfrac{Work\ done}{time}

P =\dfrac{1200}{16}

 P = 75 W

Hence, Power climber is using to climb is equal to 75 W.

3 0
3 years ago
What happens to a circuit's resistance (R), voltage (V), and current (1) when
Naya [18.7K]

Answer:

B

Explanation:

Hope this helps

4 0
2 years ago
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A concrete block (B-36 x10 °C-') of volume 100 mat 40°C is cooled to
ruslelena [56]
  • T1=40°C=313K
  • T_2=-10°C=263K

Applying Charles law

\\ \sf\Rrightarrow \dfrac{V_1}{T_1}=\dfrac{V_2}{T_2}

\\ \sf\Rrightarrow \dfrac{100}{313}=\dfrac{V_2}{263}

\\ \sf\Rrightarrow V_2=\dfrac{26300}{313}

\\ \sf\Rrightarrow V_2=84.02ml

6 0
2 years ago
According to Kepler's Third Law, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about
NARA [144]

Answer:

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Explanation:

It is given that,

Orbital radius of a solar system planet, r=4\ AU=1.496\times 10^{11}\ m

The orbital period of the planet can be calculated using third law of Kepler's. It is as follows :

T^2=\dfrac{4\pi^2}{GM}r^3

M is the mass of the sun

T^2=\dfrac{4\pi^2}{6.67\times 10^{-11}\times 1.989\times 10^{30}}\times (1.496\times 10^{11})^3    

T^2=\sqrt{9.96\times 10^{14}}\ s

T = 31559467.6761 s

T = 1.00074 years

So, a solar-system planet that has an orbital radius of 4 AU would have an orbital period of about 1.00074 years.

6 0
3 years ago
Define couple and give 2 examples
Elodia [21]

Answer:

Two equal and opposite parallel forces not acting along the same line, form a couple. A couple is always needed to produce the rotation.

For example, turning a key in a lock and turning a steering wheel.

3 0
2 years ago
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