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Anastaziya [24]
3 years ago
7

A small metal bar whose initial temperature was 20 degrees Celsius is dropped into a large container of boiling water. How long

will it take the bar to reach 90 degrees Celsius if it is known that its temperature increases 2 degrees C in 1 second. How long will it ake the bar to reach 98 C?
Physics
1 answer:
Vesnalui [34]3 years ago
4 0
Below is the answer. I hope it help.
T ( t ) = C e k t + T m where Tm is the temperature of the surroundings 
T ( t ) = C e k t + T m
T ( 0 ) = 20
T ( 1 ) = T ( 0 ) + 2 = 22
C + T m = 20 C+Tm=20 
C e k + T m = 22

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How long did Skylab orbit the earth?
maria [59]

Answer:

for abt 36 seconds

Explanation: cuz thats how long it was

4 0
3 years ago
Which part of the electromagnetic spectrum have the highest level of photon energy
Pani-rosa [81]
The energy carried by one photon is directly proportional to its
frequency.  So the photon energy is greatest for the electromagnetic
waves with the highest frequency / shortest wavelengths. 

That's why when you get past visible light and on up through ultraviolet,
X-rays, and gamma rays, the radiation becomes dangerous ==> each
photon carries enough energy to tear electrons away from their atoms,
ripping molecules apart and damaging cells.

The photon with the highest energy is a gamma-ray photon.


4 0
3 years ago
A block is attached to the end of a horizontal ideal spring and rests on a frictionless surface. The block is pulled so that the
bezimeni [28]

Answer:

The answer is "a, c and b"

Explanation:

  • Its total block power is equal to the amount of potential energy and kinetic energy.
  • Because the original block expansion in all situations will be the same, its potential power in all cases is the same.
  • Because the block in the first case has no initial speed, the block has zero film energy.
  • For both the second example, it also has the v_o velocity, but the kinetic energy is higher among the three because its potential and kinetic energy are higher.
  • While over the last case the kinetic speed is greater and lower than in the first case, the total energy is also higher than the first lower than that of the second.
  • The greater the amplitude was its greater the total energy, therefore lower the second, during the first case the higher the amplitude.
4 0
3 years ago
26. A 40 kg boy jumps from a height of 4m onto a plate-form mounted on springs. As the
denpristay [2]

Answer:

c. 1600J

Explanation:

The loss in potential energy of the boy is given by:

U=mg \Delta h

where

m = 40 kg is the mass of the boy

g = 9.8 m/s^2 is the acceleration of gravity

\Delta h = 4 m + 0.02 m = 4.02 m is the total change in the height of the boy (4 metres + 2 cm due to the compression of the spring)

Substituting, we find

\Delta U = (40 kg)(9.8 m/s^2)(4.02 m) = 1577 J \sim 1600 J

4 0
3 years ago
A 26 foot ladder is lowered down a vertical wall at a rate of 3 feet per minute. The base of the ladder is sliding away from the
lakkis [162]

Answer:

(i) 7.2 feet per minute.

(ii) No, the rate would be different.

(iii) The rate would be always positive.

(iv) the resultant change would be constant.

(v) 0 feet per min

Explanation:

Let the length of ladder is l, x be the height of the top of the ladder from the ground and y be the length of the bottom of the ladder from the wall,

By making the diagram of this situation,

Applying Pythagoras theorem,

l^2 = x^2 + y^2-----(1)

Differentiating with respect to t ( time ),

0=2x\frac{dx}{dt} + 2y\frac{dy}{dt}  ( l = 26 feet = constant )

\implies 2y\frac{dy}{dt} = -2x\frac{dx}{dt}

\implies \frac{dy}{dt}=-\frac{x}{y}\frac{dx}{dt}

We have,

y = 10, \frac{dx}{dt}= -3\text{ feet per min}

\frac{dy}{dt}=\frac{3x}{10}-----(X)

(i) From equation (1),

26^2 = x^2 + 10^2

676=x^2 + 100

576 = x^2

\implies x = 24\text{ feet}

From equation (X),

\frac{dy}{dt}=\frac{3\times 24}{10}=7.2\text{ feet per min}

(ii) From equation (X),

\frac{dy}{dt}\propto x

Thus, for different value of x the value of \frac{dy}{dt} would be different.

(iii) Since, distance = Positive number,

So, the value of y will always a positive number.

Thus, from equation (X),

The rate would always be a positive.

(iv) The length of the ladder is constant, so, the resultant change would be constant.

i.e. x = increases ⇒ y = decreases

y = decreases ⇒ y = increases

(v) if ladder hit the ground x = 0,

So, from equation (X),

\frac{dy}{dt}=0\text{ feet per min}

3 0
3 years ago
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