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insens350 [35]
2 years ago
14

4.8 tons of pig ovaries were required to extract 12.0 mg of estrogen

Chemistry
1 answer:
bearhunter [10]2 years ago
7 0
Is this a question? if so please elaborate.
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Helpppppp!!!!! It’s due today <br> URGENT!!!!!
VladimirAG [237]

Answer:

Explanation:

2. a [CO3 2-][H3O+] / [H2O][HCO3-

b. [H2PO4-][H3O+]/[H3PO4][H2O]

5 0
3 years ago
How many TOTAL carbon atoms are their in this equation? A. 1 B. 2 B.4 B. 6
telo118 [61]
What equation, love?
8 0
3 years ago
Read 2 more answers
How many atoms are in 57.5 liters of xenon gas at STP
TiliK225 [7]

Answer:

1.55 × 10²⁴ atoms Xe

General Formulas and Concepts:

<u>Atomic Structure</u>

  • Reading a Periodic Table
  • Moles
  • STP (Standard Conditions for Temperature and Pressure) = 22.4 L per mole at 1 atm, 273 K
  • Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

<u>Stoichiometry</u>

  • Using Dimensional Analysis

Explanation:

<u>Step 1: Define</u>

[Given] 57.5 L Xe at STP

[Solve] atoms Xe

<u>Step 2: Identify Conversions</u>

[STP] 22.4 L = 1 mol

Avogadro's Number

<u>Step 3: Convert</u>

  1. [DA] Set up:                                                                                                       \displaystyle 57.5 \ L \ Xe(\frac{1 \ mol \ Xe}{22.4 \ L \ Xe})(\frac{6.022 \cdot 10^{23} \ atoms \ Xe}{1 \ mol \ Xe})
  2. [DA] Divide/Multiply [Cancel out units]:                                                           \displaystyle 1.54583 \cdot 10^{24} \ atoms \ Xe

<u>Step 4: Check</u>

<em>Follow sig fig rules and round. We are given 3 sig figs.</em>

1.54583 × 10²⁴ atoms Xe ≈ 1.55 × 10²⁴ atoms Xe

4 0
3 years ago
Convert 25.4 grams of barium phosphate, Ba3(PO4)2 to formula units.
Salsk061 [2.6K]
To solve this questions you first need to find the number of moles of barium phosphate you have. The molar mass of barium phosphate is 601.93g/mol.
24.4/601.83 = 0.0402 moles barium phosphate
Then you need to use avagadro’s number, 6.022 x 10^23, which is the number of molecules or formula units in a mole.

6.022 x 10^23 * 0.0402 = 2.42 x 10^22 formula units
7 0
2 years ago
If a 0.320 mM solution of MnO41- has an absorbance of 0.480 at 525 nm in a 1.000 cm cell. What is the concentration of a MnO41-
larisa [96]

Answer:

Hence the concentration of a MnO41- solution that has absorbance of 0.490 in the same cell at that wavelength is 0.3266.

Explanation:

Now A = el, el=const

Then,

A2 / A1 = C2/ C1\\\\0.49/ 0.48 = C2 / 0.32\\\\C2 = 0.3266

3 0
3 years ago
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