Answer:
The p orbital is a lobed region describing where an electron can be found, within a certain degree of probability. All p orbitals have l = 1, with three possible values for m (-1, 0, +1).
Explanation:
1Draw a quick sketch of the object.
2Draw an arrow showing every force acting on the object.
3To calculate the net force, add any vectors acting on the same axis (x and y), making sure to pay attention to the directions.
Answer:
B) CH3CH2CH2F
Explanation:
All the other compounds listed among the options are capable of forming hydrogen bonds with water except CH3CH2CH2F.
Recall that hydrogen bonds are formed when hydrogen is directly bonded to a highly electronegative atom such as nitrogen, oxygen, fluorine, sulphur, et cetra.
Such bonds are not present in CH3CH2CH2F, rather fluorine is bonded to carbon to give a halogenoalkane. This compound will display the least solubility in water.
Answer:
Between -195°C to -215°C
Explanation:
We begin from this data:
P under -220°C will be solid, because -220°C is the freezing point.
Above -220°C, P will be at liquid state.
Then -185°C is the boling point, so above that temperature we have P as a gas.
Between -175°C to -210°C
Above -185°C we said that P is gas, so at -175°C P is not liquid. This state is F.
Between – 190°C to -225°C
At -190°C, we can have P as liquid, but -225°C is under -220°C, where P changes from liquid to solid. Then, this state is also F.
Between -200°C to -160°C
Above -185°C we said that P is gas, so at -160°C P is not liquid. This state is also F. The same, as the first situation.
Between -195°C to -215°C
-195°C is a lower temperature than -185°C. P is still liquid, we did not get the boiling point yet. -215°C is higher than -220°C, P is also liquid. There are still 5°C until P completely freezes. <em>This is the correct choice.</em>
