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3 years ago

Do two sound waves that seen equally loud always have the same amplitude? explain

1 answer:

3 0

No, because of that "seem" part of the question.

Your hearing system is not a linear sound detector and meter.
Sounds with equal amplitudes at different frequencies "seem"
to have different loudness, and the differences are different
for different people.

You've probably heard the saying "Things are not always as they seem."
The fact is, they NEVER are.

You might be interested in

Part A: Determine the wavelength of photons that can be emitted

torisob [31]

Answer:

A λ = 97.23 nm

, B) λ = 486.2 nm

, C) λ = 53326 nm

Explanation:

With that problem let's use the Bohr model equation for the hydrogen atom

$E_{n}$ = -k e² /2a₀ 1/n²

For a transition between two states we have

$E_{nf}$ - $E_{no}$ = -k e² /2a₀ (1/ $n_{f}$ ² - 1 / n₀²)

Now this energy is given by the Planck equation

E = h f

And the speed of light is

c = λ f

Let's replace

h c / λ = - k e² /2a₀ (1 / $n_{f}$ ² - 1 / no₀²)

1 / λ = - k e² /2a₀ hc (1 / $n_{f}$ ² -1 / n₀²)

Where the constants are the Rydberg constant $R_{H}$ = 1.097 10⁷ m⁻¹

1 / λ = $R_{H}$ (1 / n₀² - 1 / nf²)

Now we can substitute the given values

Part A

Initial state n₀ = 1 to the final state $n_{f}$ = 4

1 / λ = 1.097 10⁷ (1/1 - 1/4²)

1 / λ = 1.0284 10⁷ m⁻¹

λ = 9.723 10⁻⁸ m

We reduce to nm

λ = 9.723 10⁻⁸ m (10⁹ nm / 1m)

λ = 97.23 nm

Part B

Initial state n₀ = 2 final state $n_{f}$ = 4

1 / λ = 1.097 10⁷ (1/2² - 1/4²)

1 / λ = 0.2056 10⁻⁷ m

λ = 486.2 nm

Part C

Initial state n₀ = 3

1 / λ = 1,097 10⁷ (1/3² - 1/4²)

1 / λ = 5.3326 10⁵ m⁻¹

λ = 5.3326 10-5 m

λ = 53326 nm

5 0

3 years ago

The volume of water in the Pacific Ocean is about 7.00 × 108 km3. The density of seawater is about 1030 kg/m3. For the sake of t

oee [108]

The concepts used to solve this exercise are given through the calculation of distances (from the Moon to the earth and vice versa) as well as the gravitational potential energy.

By definition the gravitational potential energy is given by,

$PE=\frac{GMm}{r}$