We can use the conservation of energy to solve this problem.
We know the bullet goes in at 39m/s and leaves with 27m/s and some energy lost. We can model this using the kinetic equation energy.
The "U" is the energy lost when the bullet went through the bag. Solving for U, we get:
Next we know the bag is 48cm thick and that F*d=W, rearranging this equation we get:
F = 12.375N
Total hours is 3.35 hours
<u>Explanation:</u>
Given:
convert 3 hours 21 minutes to decimal hours
We know:
1 hour = 60 minutes
and
1 minute = 60 seconds
1 minute = 1 / 60 hours
So,
21 minutes =
= 0.35 hours
Total hours would be = 3 hours + 0.35 hours
= 3.35 hours
Therefore, total hours is 3.35 hours
As according to Kepler 's law
T =(4π²r³/ Gm)^1/2
here r= distance from earth center to satellite = 6400km = 6400000m
G = earth's gravitational constant= 6.67×10^-11
m = mass of earth= 5.98 ×10^24
so T =[ { 4× (3.1416)²×(6400000)³}/ {(6.67×10^-11)×( 5.98 ×10^24)} ]^1/2
T= 5133 sec
Objects in contact with each other never get past the electron clouds of the atoms on their surfaces.
The black circles are the solvent and the open circles are the solute