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noname [10]
4 years ago
7

Which type of device enables its users to see around corners? laser telescope microscope fiber optics

Physics
2 answers:
Doss [256]4 years ago
7 0

Answer:

D. Fiber Optics

Explanation:

Len [333]4 years ago
4 0

Answer:

Explanation: Fiber optics

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What is the best description of the destructive interference of light?
Lelechka [254]

Answer:

B. Two waves have displaced in opposite directions

Explanation:

Interference occurs when two waves meet at a point in space. When this occurs, two extreme conditions can occur:

- if the two waves are in phase (=displacement in the same direction), the amplitude of the resultant wave is equal to the sum of the amplitudes of the two waves:

A = A1 + A2

and this condition is called constructive interference

- if the two waves are in anti-phase (=displacement in opposite directions), the amplitude of the resultant wave is equal to the difference of the amplitudes of the two waves:

A = |A1 - A2|

and this condition is called destructive interference. Note that if A1=A2, the amplitude of the resultant wave is zero.

6 0
3 years ago
A centripetal force of <img src="https://tex.z-dn.net/?f=F_c" id="TexFormula1" title="F_c" alt="F_c" align="absmiddle" class="la
Minchanka [31]

Answer:

The centripetal on the car will become 4 times when the velocity gets twice.

Explanation:

As we know that centripetal force on the car of mass m and moving with constant speed v given as

F_c=\dfrac{mv^2}{r}

m=mass

v=velocity

r=radius of the circular arc

We are assuming that the mass of the both the car is same.

If the velocity of the car gets twice 2 v

The new centripetal force on the car

F_c'=\dfrac{m(2v)^2}{r}

F_c'=4\dfrac{mv^2}{r}

F_c'=4\ F_c

Therefore we can say that centripetal on the car will become 4 times when the velocity gets twice.

3 0
3 years ago
Two runners start simultaneously from the same point on a circular 200-m track and run in the same direction. One runs at a cons
sladkih [1.3K]

Answer

given,

length of the track = 200 m

speed of runner 1 = 6.20 m/s

speed of the runner 2 = 5.5 m/s

distance covered by the fastest runner, d = 6.2 t

distance covered by the slow runner,d = 5.50 t + 200

time taken to overtake for the first time

 6.2 t = 5.50 t + 200

  0.7 t = 200

       t = 285.7 s

distance covered from the starting point

 d = 6.2 t

 d = 6.2 x 285.7

 d = 1771.43 m

for next overtaking time taken will be double

 t' = 258.7 x 2 = 571.4 s

distance travel by the runner from the starting point

d' = 6.2 t'

d' = 6.2 x 571.4

d' = 3542.68 m

5 0
4 years ago
Pls help me with my work
Alenkinab [10]
I think it’s the first diagram
5 0
3 years ago
Find the acceleration of a body whose velocity increases from 11ms-1 to 33ms-1 in 10 seconds
Anvisha [2.4K]
Acceleration is equivalent to the rate of change of velocity.

Calculate the difference of velocity, and divide by the total time it took for the change to happen.

(33 \frac{m}{s}  - 11 \frac{m}{s} ) \div 10seconds \\  = 2 \frac{m}{ {s}^{2} }
That is the answer.
8 0
4 years ago
Read 2 more answers
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