The forces between the apple and Earth are the same in magnitude. Force is the same either way, but the corresponding accelerations of each are different.
Answer:
<u><em>1) if they are moving away from each other it will take 1.43 secs</em></u>
<u><em>2) if they are moving towards each other then it will take 1.11 secs</em></u>
Explanation:
Distance between them is 10 m
Speed ( if they are moving towards each other)= distance/time
time = 10/8+1
time = distance / speed= 10/9= 1.11 secs
if they are moving away from each other than it will take
time = 10/8-1= 10/7= 1.43 secs
Answer:
pf = 198.8 kg*m/s
θ = 46.8º N of E.
Explanation:
- Since total momentum is conserved, and momentum is a vector, the components of the momentum along two axes perpendicular each other must be conserved too.
- If we call the positive x- axis to the W-E direction, and the positive y-axis to the S-N direction, we can write the following equation for the initial momentum along the x-axis:

- We can do exactly the same for the initial momentum along the y-axis:

- The final momentum along the x-axis, since the collision is inelastic and both objects stick together after the collision, can be written as follows:

- We can repeat the process for the y-axis, as follows:

- Since (1) is equal to (3), replacing for the givens, and since p₀Bₓ = 0, we can solve for vfₓ as follows:

- In the same way, we can find the component of the final momentum along the y-axis, as follows:

- With the values of vfx and vfy, we can find the magnitude of the final speed of the two-object system, applying the Pythagorean Theorem, as follows:

- The magnitude of the final total momentum is just the product of the combined mass of both objects times the magnitude of the final speed:

- Finally, the angle that the final momentum vector makes with the positive x-axis, is the same that the final velocity vector makes with it.
- We can find this angle applying the definition of tangent of an angle, as follows:

⇒ θ = tg⁻¹ (1.06) = 46.8º N of E
Answer:
2872.8 N
Explanation:
We have the following information
m =n72kg
Δy = 18m
t = 0.95s.
From here we use the equation
Δy=1/2at2 in order to solve for the acceleration.
So a
=( 2x 18m)/(0.95s²)
= 36/0.9025
= 39.9m/s2.
From there we use the equation
F = ma
F=(72kg) x (39.9)
= 2872.8N.
2872.8N is the average net force exerted on him in the barrel of the cannon.
Thank you!