Newton's first law of ketchup is if the bottle of ketchup is smacked upward, the contents (the ketchup) will tend to remain in place, and it will be closer to the opening in the bottle.
<h3>Further explanation
</h3>
If we are trying to get ketchup out of the bottle, the best way to do it is to turn the bottle upside down and give the bottle a upward smack which force the bottle rapidly upward.
Newton first law said that every object tries to continue in its state of rest or uniform motion unless an external force acted upon it (In an inertial frame of reference, an object either remains at rest or continues to move at a constant velocity, unless acted upon by a force). Newton first law describe the relationship between a body and the forces acting upon it, and its motion in response to those forces.
Inertia explained by Sir Isaac Newton in his first law of motion (Newton law of motion). The law states that an object at rest stays at rest and an object continues its state of motion until an external force acts on it. The examples are one's body movement to the side when a car makes a sharp turn
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<h3>Answer details</h3>
Grade: 9
Subject: physics
Chapter: newton's first law
Keywords: newton's first law
65234. i say this because the net force is stopping the jig
Answer:
W = 20 J
Explanation:
Given that,
The mass of a loaded sack, m = 1000 g = 1 kg
It falls down from the floor of a lorry 200 cm high, h = 2 m
We need to find the work done by the gravity. The work done by an object under the action of gravity is given by :
W = mgh
Substitute all the values,
W = 1 × 10 × 2
= 20 J
Hence, the required work done by gravity is equal to 20 J.
Answer: 600N
Explanation:
Centripetal force is the force that causes a body to move in a circular path.
Centripetal force = MV²/r
M = 75kg v = 80m/s r = 0.80km = 800m
Substituting the values given in the formula;
F = 75 × 80²/800
F = 600N
The magnitude of the resultant force on the 75kg pilot is 600N.
Answer:
a) x = 40 t
, y = 39 t
, z = 6 + 32 t - 16 t
², b) x = 80 feet
, y = 78 feet
, the ball came into the field
Explanation:
a) This is a projectile launch exercise, where in the x and y axes there is no acceleration and in the z axis the acceleration of the acceleration of gravity, let's write the equations of motion in each axis
Since the cast is in the center of the field, let's place the coordinate system
x₀ = 0
y₀ = 0
z₀ = 6 feet
x-axis (towards end zone, GOAL zone)
x = xo + v₀ₓ t
x = 40 t
y-axis (field width)
y = y₀ + 
t
y = 39 t
z axis (vertical)
z = z₀ + v_{oz} t - ½ g t²
z = 6 + 32 t - ½ 32 t²
z = 6 + 32 t - 16 t
²
b) The player catches the ball at the same height as it came out, so we can find the time it takes to arrive
z = 6
6 = 6 + 32 t - 16 t²
(t - 2)t = 0
t=0 s
t= 2 s
The ball position
x = 40 2
x = 80 feet
y = 39 2
y = 78 feet
the dimensions of the field from the coordinate system (center of the field) are
x_total = 150 feet
y _total = 80 feet
so we can see that the ball came into the field
