Answer:
Explanation:
Run A Duration B Duration C Duration 1 51 48 17 2 60 48 19 3 30 39 19 4 31 48 22 5 30 31 14 6 41 16 17 7 44 12 6 8 44 12 10 9 45 43 9 10 60 41 10 Based on the simulated numbers given above, what is the average completion time of the whole project?
Since B is the predecessor of C.
Project completion time for each run will be calculated as Maximum (Duration of A, Duration of B +Duration of C).
Represent
Run = R
Duration of A = DA
Duration of B = DB
Duration of C = DC
Project Completion time = PT
<u>R DA DB DC PT</u>
1 51 48 17 48 + 17 = 65
2 60 48 19 48 + 19 = 67
4 31 48 22 48 + 22 = 70
5 30 31 14 31 + 14 = 45
6 41 16 17 41
7 44 12 6 44
8 44 12 10 44
9 45 43 9 43 + 9 = 52
10 60 41 10 60
<u> Total = 546</u>
Total Project completion time in 10 Stimulations = 546
Average project Completion time = 546/10 = 54.6
Therefore, average Project completion time is between 53 and 56 days.
Answer:
the market quantity supplied is less than 250 scoops when the price is $2 per scoop
Explanation:
When price is $2, the total quantity supplied = 20 + 50 + 35 + 100 + 40 = 245
At the price $2, the total quantity supplied is less than 245
Currently, I would say LEAN and Six Sigma.
Answer:
The journal entry to record the bond issuance is shown below:
Explanation:
The journal entry to record the bond issuance is as:
Cash A/c.............................................Dr $420,000
Bonds Payable A/c......................Cr $420,000
Being the bonds issued
As the bonds are issued by the company so cash is coming into the business, which is an asset and any increase in asset is debited. Therefore, the cash account is debited. And cash is received against the bonds payable, so the account of bonds payable is credited.