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musickatia [10]
3 years ago
11

In the living room of your house you would like to run a 360 W stereo, a 30 W computer, a 720 W laser light projector, and four

60 W lights. Assuming your house is wired for 120 Volts, how much current will be pulled by these electrical devices
Physics
1 answer:
Sauron [17]3 years ago
8 0

Answer:

9.75 A.

Explanation:

Current: This can be defined as the rate of flow of electric charge in a circuit.

Note: Total power in the living room = 360 W + 30 W + 720 W + 60 W = 1170 W.

Using the formula of electric power,

P = VI ........................... Equation 1

Where P = Total power in the living room, V = Voltage, I = current.

Make I the subject of the equation,

I = P/V .......................... Equation 2

Given: P = 1170 W, V = 120 V.

Substitute into equation 2

I = 1170/120

I = 9.75 A.

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What is the freezing point of radiator fluid that is 50% antifreeze by mass? k f for water is 1.86 ∘ c/m?
densk [106]
Ethylene glycol is termed as the primary ingredients in antifreeze.
The ethylene glycol molecular formula is C₂H₆O₂.
Molar mass of C₂H₆O₂ is = (2×12) +(6×1) + (216) = 62g/mol
Now that antifreeze by mass is 50%, then there is 1kg of ethylene glycol which is present in 1kg of water.
ΔTf = Kf×m
ΔTf = depression in the freezing point.
= freezing point of water freezing point of the solution
= O°c - Tf
= -Tf
Kf = depression in freezing constant of water = 1.86°C/m
M is the molarity of the solution.
=(mass/molar mass) mass of solvent in kg
=1000g/62 (g/mol) /1kg
=16.13m
If we plug the value we get 
-Tf = 1.86 × 16.13 = 30
Tf = -30°c
7 0
3 years ago
Read 2 more answers
State a situation in which force is applied on a body, but no work is done​
LenaWriter [7]
If you press on your arm force is applied work done is if it moves.
One answer could be if I was to press my hand on a table.
Have a great day!
8 0
3 years ago
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What is most likely to happen to light that hits an opaque object?
ddd [48]
B. is the answer.

C is not correct because the light is actually reflected off of an opaque object.
4 0
3 years ago
A 50-gram sample of water is initially at a temperature of 22 °C. The sample is heated until the temperature is 32 °C The specif
forsale [732]

Answer:

500cal

Explanation:

Given parameters:

Mass of water  = 50g

Initial temperature  = 22°C

Final temperature  = 32°C

Specific heat of water  = 1cal/g

Unknown:

Amount of heat absorbed by the water in calories  = ?

Solution:

To solve this problem, we use the expression below:

       H  = m c Ф

H is the amount of heat absorbed

m is the mass

c is the specific heat capacity

Ф is the temperature change

       H  = 50 x 1 x (32  - 22)  = 500cal

5 0
2 years ago
the total positive charge is QQQ = 1.62×10−6 CC , what is the magnitude of the electric field caused by this charge at point P,
balu736 [363]

Answer:

6.1 × 10^9 Nm-1

Explanation:

The electric field is given by

E= Kq/d^2

Where;

K= Coulombs constant = 9.0 × 10^9 C

q = magnitude of charge = 1.62×10−6 C

d = distance of separation = 1.53 mm = 1.55 × 10^-3 m

E= 9.0 × 10^9 × 1.62×10−6/(1.55 × 10^-3 )^2

E= 14.58 × 10^3/2.4 × 10^-6

E= 6.1 × 10^9 Nm-1

8 0
3 years ago
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