Answer:
The percentage composition of each element in H2O2 is 5.88% H and 94.12% O (Option D).
Explanation:
Step 1: Data given
Molar mass of H = 1.0 g/mol
Molar mass of O = 16 g/mol
Molar mass of H2O2 = 2*1.0 + 2*16 = 34.0 g/mol
Step 2: Calculate % hydrogen
% Hydrogen = ((2*1.0) / 34.0) * 100 %
% hydrogen = 5.88 %
Step 3: Calculate % oxygen
% Oxygen = ((2*16)/34)
% oxygen = 94.12 %
We can control this by the following equation
100 % - 5.88 % = 94.12 %
The percentage composition of each element in H2O2 is 5.88% H and 94.12% O (Option D).
765.75
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Answer:
A, organic chemist
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that is a pretty cool job lol!!
Answer: Option (3) is the correct answer.
Explanation:
Atomic number of lithium is 3 and atomic number of bromine is 35. So, lithium has one extra electron whereas bromine has deficiency of one electron according to the octet rule.
Thus, when lithium combines with bromine then it results in the formation of ionic bond. That is, bond formed by transfer of electrons is known as ionic bond.
Thus, lithium loses one electron and becomes a positively charged ion.
<h3>
Answer:</h3>
11.3 mol Ba(NO₃)₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structure</u>
- Using Dimensional Analysis
- Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
6.80 × 10²⁴ molecules Ba(NO₃)₂
<u>Step 2: Identify Conversions</u>
Avogadro's Number
<u>Step 3: Convert</u>
- Set up:
- Multiply:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
11.2919 mol Ba(NO₃)₂ ≈ 11.3 mol Ba(NO₃)₂