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gayaneshka [121]
3 years ago
9

A gas gas a volume of 4.0 liters at a pressure of 0.80 atm. What is the volume if the pressure is changed to 0.40 atm at a const

ant temp
Chemistry
1 answer:
Anastaziya [24]3 years ago
3 0

Answer:

The volume is 8,0 L.

Explanation:

We apply Boyle Mariotte's Law: for a given mass of gas at constant temperature, its pressure and volume vary inversely proportionally (the higher the pressure, the lower the volume and vice versa):

P1 x V1 = P2 xV2

V2 = (P1 x V1)/P2

V2 = ( 0,80 atm x 4,0 L)/ 0,40 atm

<em>V2= 8,0 L</em>

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Using the reaction below: 2 CO2(g) + 2 H2O(l) → C2H4(g) + 3 O2(g) ΔHrxn= +1411.1 kJ What would be the heat of reaction for this
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Heat of reaction is the change of enthalpy during a chemical reaction with all substances in their standard states.

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7 0
3 years ago
A sample of gas occupies 10.0 L at 240°C under a pressure of
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Answer: 1090°C

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(P1 × V1) ÷ T1 = (P2 × V2) ÷ T2

where P1 = initial pressure of gas = 80.0 kPa

V1 = initial volume of gas = 10.0 L

T1 = initial temperature of gas = 240 °C = (240 + 273) K = 513 K

P2 = final pressure of gas = 107 kPa

V2 = final volume of gas = 20.0 L

T2 = final temperature of gas

Substituting the values,

(80.0 kPa × 10.0 L) ÷ (513 K) = (107 kPa × 20.0 L) ÷ T2

T2 = 513 K × (107 kPa ÷80.0 kPa) × (20.0 L ÷ 10.0 L)

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T2 = 1372.275 K

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T2 = 1099 °C

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