10 cm3 because the density equition is d = m/v
Answer:
Explanation:
Total tension must support the weight of the child and provide the necessary centripetal force.
2T = m(g + v²/R)
2(414) = 35.0(9.81 + v²/3.02)
828 = 35.0(9.81 + v²/3.02)
23.65 = 9.81 + v²/3.02
13.847 = v²/3.02
41.81 = v²
v = 6.47 m/s
F = 2(414) = 828 N (ignoring the weight of the chains and seat)
if your vehicle begins to slide or skid in the rear, you should steer in the direction that the rear is sliding to.
<h3>What should you do if the rear end of the vehicle starts to slide or skid?</h3>
In the case above, a person need to Look as well as steer in the direction that the person want the front of the vehicle to go.
Note that in the case above;
Do stay way from the brake pedal and never apply the brakes.
- Steer in the the same direction as the rear of the vehicle that is known to be sliding. This will give room for the vehicle to go straight instead of going sideways.
- Then make sure to get ready to steer in the opposite direction if the vehicle is one that begins swerving in the other direction.
Therefore, if your vehicle begins to slide or skid in the rear, you should steer in the direction that the rear is sliding to.
Learn more about slide or skid from
brainly.com/question/2148046
#SPJ1
Because the silt (dirt particles) in muddy water eventually settles out, the muddy water is a __suspension__ .
Answer:
![r_{final}=r_{i}/4](https://tex.z-dn.net/?f=%20r_%7Bfinal%7D%3Dr_%7Bi%7D%2F4)
Explanation:
We know force between 2 charges is given by
![F=\frac{1}{4\pi \varepsilon }\frac{q_{1}q_{2}}{r^{2}}](https://tex.z-dn.net/?f=F%3D%5Cfrac%7B1%7D%7B4%5Cpi%20%5Cvarepsilon%20%7D%5Cfrac%7Bq_%7B1%7Dq_%7B2%7D%7D%7Br%5E%7B2%7D%7D)
It is given initial force is attractive of magnitude![F_{i}](https://tex.z-dn.net/?f=F_%7Bi%7D)
Let
be the initial separation
Thus
![F_{i}=\frac{1}{4\pi \varepsilon }\frac{q_{a}q_{b}}{r_{i}^{2}}](https://tex.z-dn.net/?f=F_%7Bi%7D%3D%5Cfrac%7B1%7D%7B4%5Cpi%20%5Cvarepsilon%20%7D%5Cfrac%7Bq_%7Ba%7Dq_%7Bb%7D%7D%7Br_%7Bi%7D%5E%7B2%7D%7D)
Now
Let
be the final separation
Thus final force becomes
![\frac{1}{4\pi \varepsilon }\frac{q_{a}q_{b}}{r_{f}^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%5Cpi%20%5Cvarepsilon%20%7D%5Cfrac%7Bq_%7Ba%7Dq_%7Bb%7D%7D%7Br_%7Bf%7D%5E%7B2%7D%7D)
It is given
=
...................(i)
Using values of
and
in equation i we have
= ![\frac{1}{4\pi \varepsilon }\frac{q_{a}q_{b}}{r_{f}^{2}}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%5Cpi%20%5Cvarepsilon%20%7D%5Cfrac%7Bq_%7Ba%7Dq_%7Bb%7D%7D%7Br_%7Bf%7D%5E%7B2%7D%7D)
thus
![thus\\\\(\frac{r_{i}}{r_{f}})^{2}=16\\\\\frac{r_{i}}{r_{f}}=4\\\\\therefore r_{f}=r_{i}/4](https://tex.z-dn.net/?f=thus%5C%5C%5C%5C%28%5Cfrac%7Br_%7Bi%7D%7D%7Br_%7Bf%7D%7D%29%5E%7B2%7D%3D16%5C%5C%5C%5C%5Cfrac%7Br_%7Bi%7D%7D%7Br_%7Bf%7D%7D%3D4%5C%5C%5C%5C%5Ctherefore%20r_%7Bf%7D%3Dr_%7Bi%7D%2F4)
Thus the final separation is one-fourth of the initial separation