All categories

3 years ago

What must you learn before you ca calculate you target heart rate for exercise

1 answer:

8 0

You must learn your resting heart rate, rate at which your heart beats during excerpts and etc you pretty much just need a heart rate monitor

You might be interested in

A 2.0 kg stone is tied to a 0.30 m string and swung around a circle at a constant angular velocity of 12.0 rad/s. The net torque

saul85 [17]

Answer: τ = 0

Explanation:

At constant angular velocity there is no angular acceleration therefore no torque.

τ = Iα

6 0

3 years ago

The density of a glass is 2.5 g/cm3. if the glass breaks, what is the density of the smaller pieces

sp2606 [1]

Answer:

See the explanation below.

Explanation:

Density will remain the same since density is the relationship between mass and volume. As we can see in the equation below.

$Ro=m/V$

where:

Ro = density = 2.5 [g/cm³]

m = mass [g]

V = volume [cm³]

In such a way that when the glass is broken the small fragments retain the same density ratio. That is, each fragment has a small mass and a small volume. That's why the density remains the same.

4 0

3 years ago

Ben and Dan both weigh 600 N. They are doing pull-ups together. Each pull-up is 0.5 meters of distance. How much work do they ea

Natasha2012 [34]

Answer:

300 J

Explanation:

Work = (Force)*(distance) = 600 N ∗ 0.5 m = 300 J

5 0

2 years ago

A 50.0 kg object rests on a horizontal surface. The coefficient of static friction between the box and the surface is 0.300 and

MariettaO [177]

Answer:

$f=140\ N$

Explanation:

Given:

mass of the object on a horizontal surface, $m=50\ kg$

coefficient of static friction, $\mu_s=0.3$

coefficient of kinetic friction, $\mu_k=0.2$

horizontal force on the object, $F=140\ N$

<u>Now the value of limiting frictional force offered by the contact surface tending to have a relative motion under the effect of force:</u>

$F_s=\mu_s.N$

where:

$N=$ normal force of reaction acting on the body= weight of the body

$F_s=0.3\times (50\times 9.8)$

$F_s=147\ N$

As we know that the frictional force acting on the body is always in the opposite direction:

So, the frictional force will not be at its maximum and will be equal in magnitude to the applied external force and hence the body will not move.

so, the frictional force will be:

$f=140\ N$

8 0

3 years ago

Which statement about elements and atoms is true?

Vika [28.1K]

Atoms are the smallest unit of an element

8 0

3 years ago