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Ivenika [448]
3 years ago
11

A car is traveling at 30 m/s in a straight line. The drive applies the brakes for 3 seconds and the car slows down to 12 m/s. Wh

at is the acceleration of the car?
Physics
1 answer:
jeyben [28]3 years ago
3 0

Answer:

The answer to your question is: -6m/s²

Explanation:

Data

vo = 30 m/s

vf = 12 m/s

t = 3 s

a = ?

Formula

vf = vo + at

a = (vt - vo) / t

Process

                a = (12 - 30) / 3                substitution

                a = -18 / 3                         simplify

                a = -6 m/s²                        result, is negative because the car

                                                          is slowing down.

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Answer:

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Explanation:

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8 0
3 years ago
Which way does the friction arrow go in a free body diagram for a moving object point
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Answer:

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Explanation:

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The main component of the contact force of two objects is normal force and that is in the perpendicular direction.  Frictional force is other complnent. This frictional force is parallel to the interface between objects. Frictional force opposes relative motion between surfaces.

7 0
4 years ago
Read 2 more answers
Two loudspeakers are placed on a wall 3.00 m apart. A listener stands 3.00 m from the wall directly in front of one of the speak
Mashutka [201]

Answer:

Part a)

\Delta \phi = 2.2 \pi

Part b)

f = 411.3 Hz

Explanation:

As we know that the observer is standing in front of one speaker

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\Delta x = 3\sqrt2 - 3

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now phase difference is related with path difference as

\Delta \phi = \frac{2\pi}{\lambda}(\Delta x)

\Delta \phi = \frac{2\pi}{\lambda}(1.24)

here in order to find the wavelength

\lambda = \frac{c}{f}

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now we have

\Delta \phi = \frac{2\pi}{1.13}(1.24) = 2.2\pi

Part b)

Now we know that when phase difference is odd multiple of \pi

then in that case the the sound must be minimum

So nearest value for minimum intensity would be

\Delta \phi = 3\pi

so we have

3\pi = \frac{2\pi}{\lambda}(1.24)

so we have

\lambda = 0.827

now we have

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