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densk [106]
4 years ago
11

A solution made by dissolving 14.2g of sucrose in 100g water exhibits a freezing point depression of 0.77 degrees. Calculate the

molar mass of sucrose
Chemistry
1 answer:
Nataly [62]4 years ago
5 0

For the purpose we have to know following equation for freezing point depression:


ΔTf=Kf*b


and that Kf of water is 1.86°C/m.


From the formula we can determine molality (b):


b=Δtf/Kf=0.77/1.86= 0.414 mole/kg


Now when we know molality, we can calculate mass of sucrose in solution:


b=n/m(H20)   =>  n(sucrose)=b*m(H20) = 0.414 mole/kg *0.1 kg = 0.0414 mole


Finally, we can determine the molar mass of sucrose:


M=m/n=14.2/0.0414= 343g/mole

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dimaraw [331]

The reactants that will form products will be 2CuI_2 + Br2.

<h3>Activity series</h3>

Elements at higher positions in the activity series will be able to displace those in lower positions in solutions.

Thus:

2CuI_2 + Br2 --- > 2CuBr +2 I_2 because Br is higher than I in the activity series.

Cl cannot displace F in Cl2 + AlF_3 because F is higher than Cl in the activity series.

Also, Cl is higher than Br in the activity series, thus, the reaction Br_2 + NaCl cannot form products.

I cannot displace F, thus, CuF_2 + I_2 cannot form products.

More on activity series can be found here: brainly.com/question/13934381

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2 years ago
Simplify 8k-5(-5k+3)
antiseptic1488 [7]

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7 0
3 years ago
Suggest why some manufacturers of car and jewellery would use metal alloys instead of pure metals?
nika2105 [10]
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3 years ago
At a pressure of 9.25×10−14 atm and an ordinary temperature of 300.0 K , how many molecules are present in a volume of 1.10 cm3
statuscvo [17]

Answer:

2.49 × 10⁶ molecules

Explanation:

Given data

  • Pressure (P): 9.25 × 10⁻¹⁴ atm
  • Temperature (T): 300.0 K
  • Volume (V): 1.10cm^{3} .\frac{1mL}{1cm^{3}} .\frac{1L}{1000mL} =1.10\times 10^{-3} L

We can calculate the moles of gas using the ideal gas equation.

P × V = n × R × T

n = P × V / R × T

n = 9.25 × 10⁻¹⁴ atm × 1.10 × 10⁻³ L / (0.0821 atm.L/mol.K) × 300.0 K

n = 4.13 × 10⁻¹⁸ mol

1 mole contains 6.02 × 10²³ molecules (Avogadro's number). The number of molecules in 4.13 × 10⁻¹⁸ moles is:

4.13 × 10⁻¹⁸ mol × (6.02 × 10²³ molecule/1 mol) = 2.49 × 10⁶ molecule

7 0
3 years ago
In an experiment, 2.54 grams of copper completely reacts with sulfur, producing 3.18 grams of copper(I) sulfide.
kozerog [31]

Answer:

               0.64 g of S

Solution:

               The balance chemical equation is as follow,

                                           2 Cu + S ----> Cu₂S

According to equation,

                        127 g (2 mole) Cu produces = 159 g (1 mole) of Cu₂S

So,

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Solving for X,

                     X = (2.54 g * 159 g) / 127 g

                     X = 3.18 g of Cu₂S

Now, it is confirmed that the reaction is 100% ideal. Therefore,

As,

                       127 g (2 mole) Cu required = 32 g (1 mole) of S

So,

                                2.54 g Cu will require = X g of S

Solving for X,

                      X = (2.54 g * 32 g) / 127 g

                      X = 0.64 g of S

5 0
3 years ago
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