4.3 x 10⁻⁸dm⁻²
Explanation:
Problem:
To solve this problem, we have apply the right rule of indices operation.
If we have an indices in the form;
= (
)
Solving this problem:
= 
x 10
)
= 0.43 x 10⁻⁷
= 4.3 x 10⁻¹ x 10⁻⁷
= 4.3 x 10⁻⁸
for the units:
= 
The solution is: 4.3 x 10⁻⁸dm⁻²
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With reference to the solutions, following things may be noted
1) Homogeneous solutions comprises of single phase.
2) Heterogeneous solution comprises of more than one phase.
3) in colloidal solution, solute is evenly distributed in solvent. in such system, it is difficult to separate solute and solvent.
4) in suspension, there is an uneven distribution of solute in solvent. In such system, solute and solvent gets separated on standing long.
Blood is a homogeneous and colloidal solution,
Salad dressing is a heterogeneous and suspension solution.
Answer:
salt in the Dead Sea is sodium chloride
while salt in the lab is either soluble or
insoluble in water.
Explanation:
The term 'salt' in the school laboratory does not always refer to sodium chloride. It is a generic term used for many substances especially those substances formed by neutralization reaction.
There are many salts that are used in the laboratory. Some of these salts are soluble in water while some are not soluble in water.
Salt in the dead sea always refers to sodium chloride, hence, salt in the dead sea is different from salt in the school laboratory.
Answer:
I think its ethanol based on what I've learned
<u>Answer:</u> The rate constant for the reaction is 
<u>Explanation:</u>
Rate law expression for first order kinetics is given by the equation:
![k=\frac{2.303}{t}\log\frac{[A_o]}{[A]}](https://tex.z-dn.net/?f=k%3D%5Cfrac%7B2.303%7D%7Bt%7D%5Clog%5Cfrac%7B%5BA_o%5D%7D%7B%5BA%5D%7D)
where,
k = rate constant = ?
t = time taken for decay process = 2.00 min = 120 seconds (Conversion factor: 1 min = 60 seconds)
![[A_o]](https://tex.z-dn.net/?f=%5BA_o%5D)
= initial amount of the sample = 100 grams
[A] = amount left after decay process = 20 grams
Putting values in above equation, we get:
Hence, the rate constant for the reaction is
