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notsponge [240]
2 years ago
9

What is FGD /Flue gas desulfurization is used for?

Chemistry
1 answer:
VladimirAG [237]2 years ago
3 0

Answer: Flue-gas desulfurization (FGD) material is a product of a process typically used for reducing SO2 emissions from the exhaust gas system of a coal-fired boiler.

Explanation:

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TRUE or FALSE
andriy [413]

Answer:

1. true

2. false

3. true

Explanation:

5 0
2 years ago
Determine the primary structure of an octapeptide from the following data: acid-catalyzed hydrolysis gives 2 arg, leu, lys, met,
erma4kov [3.2K]

Complete Question

The complete question is shown on the first uploaded image

Answer:

The sequence of these amino acid would be

          <u>Lue</u>  <u>Arg</u>  <u>Lys</u>  <u>Arg</u>  <u>Met</u>  <u>Phe</u> <u>Arg</u>  <u>Ser</u>

Explanation:

The acid-catalyzed hydrolysis from makes us to understand that the  polypeptides contains 8 amino acids

   From the question we are told that the Edman's reagent releases Leu it means that the N-terminal amino acid would be Lue(i.e Leucine)

     Also from the question we are told that the Carboxypeptidase  released Ser this mean the the C-terminal  amino acid would be Ser ( i.e Serine)

   The Amino acids would in the polypeptides would be arranged like this  

         

         <u>Lue</u> __  __  __  __  __ __  <u>Ser</u>

Now from the question we are told that treatment with cranogen bromide form two peptides.

   Now generally  cranogen bromide divides a peptide on  the C- side(i.e the extreme left side ) of  Met(Methionine)(This is an amino acid obtained by hydrolysis of most common peptides )

   So this means that any peptides  containing Met(Methionine) must have Methionine as a C- terminal amino acid(i.e at extreme left) and for peptides that does not contain Met must be C - terminal peptides

From the question we see that it is the second peptide that contain Met and it is a penta peptide(i.e it contains 5 amino acid)  

    Thus the fifth amino acid is  Met  

So the sequence of these amino acid would now be  

          <u>Lue</u> __  __  __  <u>Met</u>  __ __  <u>Ser</u>

From the question we are told that the the Trypsin-catalyzed hydrolysis forms two amino acid and two peptides  

   Now generally Trypsin divides a peptide  on the  C- side(i.e the extreme left) of Arg(Arginine) and Lys (lysine) and any peptide that holds Arg or Lys  must have them as their C- terminal  amino acids

   From the first peptide in the two peptide formed we see that  Arg would be the Seventh amino acid of the octapeptide because commonly the trypsin that sticks to the C-side of Arg would for Ser

and Phe would be the sixth amino acid of the octapeptide

So the sequence of these amino acid would be

       <u>Lue</u> __  __  __  <u>Met</u>  <u>Phe</u> <u>Arg</u>  <u>Ser</u>

Looking  at the first amino acid formed from the Trypsin-catalyzed hydrolysis  we see that Arg would be the fourth amino acid of  octapeptide      as Trypsin divides a peptide  on the  C- side(i.e the extreme left) of Arg(Arginine).

From the second peptide of the  Trypsin-catalyzed hydrolysis  we see that Lys would be the third amino acid of the octapeptide as trypsin divides on the  C- side of  Lys (lysine) and Tyr would be the second amino acid of the octapeptide

So the sequence of these amino acid would be

          <u>Lue</u>  <u>Arg</u>  <u>Lys</u>  <u>Arg</u>  <u>Met</u>  <u>Phe</u> <u>Arg</u>  <u>Ser</u>

           

4 0
3 years ago
If a body were a car glucose would be?
Elden [556K]
Glucose is chemical energy for the body, as gasoline (petrol) is chemical energy for the car. Thus, gasoline.
6 0
3 years ago
Read 2 more answers
Can arsenic be broken down by a chemical change
anygoal [31]
Arsenic is a pure element. Elements (atoms) are the simplest building blocs excluding smaller elementary particles such as electrons, neutrons, quarks, protons etc. 

This means that Arsenic can not be broken down any further by chemical change, only nuclear decay can cause the breakdown of large elements into smaller ones. Chemical change would be the combination of multiple elements into a compound or the decomposition of a molecule/compound into pure elements or smaller compounds. 
7 0
2 years ago
Why was it necessary to make sure that some solid was present in the main solution before taking the samples to measure Ksp?
padilas [110]

The question is incomplete, the complete question is;

Why was it necessary to make sure that some solid was present in the main solution before taking the samples to measure Ksp? Select the option that best explains why. Choose... A. To make sure no more sodium borate would dissolve in solution. B. To ensure the dissolution process was at equilibrium. C. To make sure the solution was saturated with sodium and borate ions. D. All of the above

Answer:

B. To ensure the dissolution process was at equilibrium.

Explanation:

The solubility product is a term used in chemistry to describe the equilibrium between the dissolved, dissociated and undissolved solute of a relatively low solubility ionic solid.

For an ionic solid MX, the solubility product is given as ;

MX(s) ----> M^n+(aq) + X^n-(aq)

If Ksp indeed scribes an equilibrium process for dissolution, it then implies that some undissolved solute must be present before samples are taken to measure the Ksp of a sample. This ensures equilibrium between dissolved and undissolved solute.

7 0
3 years ago
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