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nadya68 [22]
2 years ago
6

Q. 1 MWH is equal to ------- joules a.3.6*10^10 b.3.6*10^6 c.3.6*10^9 d.3.6

Physics
1 answer:
umka2103 [35]2 years ago
5 0
Correct option is B
1 kWh is equal to 3.6 × 10
6

1 Watt-sec is a Joule a watt expended for a second.
Because there’s 3600 seconds in an hour,
then 3600 Ws = 1 Wh = 3600 Joules = 3.6 kJ
so 1000 Wh = 1 kWh = 1000 × 3.6 kJ = 3.6 MJ = 3.6 × 10
6
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A point charge of 9.00 × 10−9 C is located at the origin of a coordinate system. A positive charge of 3.00 × 10−9 C is brought i
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A point charge is located at the origin of a coordinate system. A positive charge is brought in from infinity to a point. The charges are at distance for given electrical potential energy is 3.34 x  10⁷ m.

<h3>What is electric potential energy?</h3>

The electric potential energy is the work done by a test charge to bring it from infinity to a particular location.

The electric potential energy is given by the relation,

V = kQ/r

where k = 9 x 10⁹ J.m/C ,Q = 3 x 10⁻⁹ C, V =8.09 × 10⁻⁷ J.

Substitute the values into the expression to get the distance between the charges.

8.09 × 10⁻⁷ =  9 x 10⁹ x  3 x 10⁻⁹ / r

r =3.34 x  10⁷ m

Thus, the distance between the charges will be 3.34 x  10⁷ m.

Learn more about  electric potential energy.

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4 years ago
The ???? ,of an object is a vector that is directed toward<br> the center of the Earth.
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3 years ago
What is the voltage drop across an alarm clock that is connected to a circuit with a current of 1.10A and a resistance of 90Ω?
vfiekz [6]

V = 99 volts

Explanation:

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8 0
3 years ago
An elevator's electric hoist is rated at 8.0 kW and has an efficiency of 90.0%. The hoist lifts the elevator car, mass 1225 kg,
Nataly_w [17]

Part a)

Power rated on the elevator is given as

P = 8 kW

P = 8 \times 10^3 W

now the mass that is lifted above is given as

m = 1225 kg

height of the elevator lifted is

h = 9 m

now the potential energy is given as

U = mgh

U = 1225 (9.8)(9) = 108045 J

now power is defined as rate of energy

P = \frac{W}{t}

8 \times 10^3 = \frac{108045}{t}

t = 13.5 s

so it will take 13.5 s to lift up

Part b)

Electrical energy used

efficiency = 90

0.90 = \frac{Output}{Input}

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Input = 120050 J

so electrical energy used in this process will be 120050 J

6 0
4 years ago
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