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Effectus [21]
1 year ago
11

You can switch the polarity of the bar magnet by clicking on the button with the bar magnet and two semi-circular arrows on the

bottom right. Note how the positions of the north and south poles are switched every time you click on this button. Drag the bar magnet from left to right through the top coil, then repeat the same process after switching the polarity of the magnet. What effect, if any, does switching the polarity have on the brightness of the bulb and the needle of the voltmeter
Physics
1 answer:
lana [24]1 year ago
7 0

The effect that is seen is that the brightness of the bulb is unaffected by switching the polarity of the magnet; however, the order in which the needle deflects on the voltmeter is flipped when you do so.

This is further explained below.

<h3>What is switching the polarity?</h3>

Generally, When the polarity is reversed, both the hot wire and the neutral wire are switched, which causes the electric current to flow in the opposite direction. Because of this, the electric current enters the appliance through the neutral terminal rather than the hot terminal, which energizes the appliance even when it is turned off.

In a worst-case scenario, the battery's shell might burst apart due to the heat generated by the polarity reversal, which would release hydrogen gas, which is flammable. Acid from the battery may leak out of the box and burn you or damage your expensive electronics.

In conclusion, In this case, reversing the magnet's polarity has no impact on the light output of the bulb, but it does reverse the direction of the voltmeter's needle deflection.

Read more about switching the polarity

brainly.com/question/14600686?

#SPJ1

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a wire of a certain material has resistance r and diameter d a second wire of the same material and length is found to have resi
777dan777 [17]

Answer:

<h2>d₂ = 3d</h2><h2>The diameter of the second wire is 3 times that of the initial wire.</h2>

Explanation:

Using the formula for calculating the resistivity of an object to find the diameter.

Resistivity P = RA/L

R is the resistance of the material

A is the cross sectional area

L is the length of the material

Since A = πd²/4

P = R( πd²/4)/L

P = Rπd²/4L ... 1

If the second wire of the same material and length is found to have resistance R/9, the resistivity of the second material will be;

P₂ = (R/9)A₂/L₂

P₂ = (R/9)(πd₂²/4)/L₂

P₂ = (Rπd₂²/36)/L₂

P₂ = (Rπd₂²)/36L₂

Since the length and resistivity are the same;

P = P₂  and L =L₂

Equating 1 and 2;

Rπd²/4L =  (Rπd₂²)/36L₂

Rπd²/4L =  (Rπd₂²)/36L

d² = d₂²/9

d₂² = 9d²

Taking the square root of both sides;

√d₂² = √9d²

d₂ = 3d

Therefore the diameter of the second wire is 3 times that of the initial wire

5 0
3 years ago
Amy is standing still on the ground; Bill is riding his bicycle at 5 m/s eastward; and Carlos is driving his car at 15 m/s westw
Solnce55 [7]

Answer:

20 m/s westward

Explanation:

Taking eastward as positive direction, we have:

v_B = +5 m/s is the velocity of Bill with respect to Amy (which is stationary)

v_C = -15 m/s is the velocity of Carlos with respect to Amy

Bill is moving 5 m/s eastward compared to Amy at rest, so the velocity of Bill's reference frame is

v_B = +5 m/s

Therefore, Carlos velocity in Bill's reference frame will be

v_C' = v_C - v_B = -15 m/s - (+5 m/s) = -20 m/s

and the direction will be westward (negative sign).

3 0
3 years ago
How many legs does an arachnid have??
Virty [35]
An arachnid has eight legs.
6 0
3 years ago
8. Mark is sitting in a chair, legs out in front of him resting on an ottoman. His knees are.....
anyanavicka [17]
His knees are flat in front of him or 180 degrees, i hope that answered your question   
5 0
3 years ago
Read 2 more answers
A positively charged particle Q1 = +35nC is held fixed at the origin. A second charge of mass m = 3.5ug is floating a distance d
cupoosta [38]

Answer:

Explanation:

Q1 = 35 nC = 35 x 10^-9 C

m = 3.5 micro gram = 3.5 x 10^-9 Kg

d  = 35 cm = 0.35 m

(a) The electrostatic force between the two charges is balanced by the weight of another charge.

F = m g

\frac{1}{4\pi \epsilon _{0}}\frac{Q_{1}Q_{2}}{d^{2}}=mg

Q_{2}=\frac{4\pi \epsilon _{0}mgd^{2}}{Q_{1}}

(b) By substituting the values

Q_{2}=\frac{3.5\times 10^{-9}\times 9.8\times 0.35\timees 0.35}{9\times 10^{9}\times 35\times 10^{9}}

Q2 = 13.34 x 10^-12 C

Q2 = 0.0134 nC

4 0
3 years ago
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