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Sidana [21]
4 years ago
6

NaOH, KOH, and Ca(OH)2 are examples of (4 points)

Chemistry
1 answer:
dezoksy [38]4 years ago
8 0
Bases...
Acid are those contain H+ ions...
Bases/alkali are those with OH- ions
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Which gas law can you use to solve for moles of gas
Sergio [31]

Answer:

it would be the ideal gas law also known as Avagadro's law

Explanation:

4 0
3 years ago
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Classify each of the following as a Strong acid (sa) or a Weak acid (wa) and indicate how each should be written in aqueous solu
bazaltina [42]

Answer:

1. wa. Molecular form.

2. wa. Molecular form.

3. sa. Ionic form.

Explanation:

1. hydrocyanic acid

HCN is a weak acid. That means that in the following equilibrium, the molecular form (HCN(aq)) is favored, and that's how it should be written in solution.

HCN(aq) ⇄ H⁺(aq) + CN⁻(aq)

2. hypochlorous acid

HClO is a weak acid. That means that in the following equilibrium, the molecular form (HClO(aq)) is favored, and that's how it should be written in solution.

HClO(aq) ⇄ H⁺(aq) + ClO⁻(aq)

3. hydrochloric acid

HCl is a strong acid. That means that it completely dissociates and it should be written in the ionic form (H⁺(aq) + Cl⁻(aq)) when it is in solution.

HCl(aq) → H⁺(aq) + Cl⁻(aq)

3 0
3 years ago
Which statement best describes the way a catalyst works?
bogdanovich [222]

Answer: E. It decreases the value of Eact.

Explanation:

Activation energy is the extra energy that must be supplied to reactants in order to cross the energy barrier and thus convert to products.

A catalyst is a substance which increases the rate of a reaction by taking the reaction through a different path which involves lower activation energy and thus more molecules can cross the energy barrier and more molecules convert to products.

The catalyst itself does not take part in the chemical reaction and is regenerated as such at the end.

6 0
3 years ago
A sample of carbon-12 has a mass of 6.00 g. How
dexar [7]

Answer:

#atoms C-12 = 3.01 x 10²³

Explanation:

Convert grams to moles and multiply by Avogadro's Number.

6 g C-12 = (6g/12g·mol⁻¹) = 0.50 mol C-12

No. C-12 atoms in 0.50 mol C-12 = 0.50 mol C-12 x 6.02E23 atoms/mole = 3.01E23

8 0
3 years ago
A 36.2 g object has a heat capacity of 12.5 J/ oC. How much energy (in J) is required to raise the temperature by 5.73 oC?
iren2701 [21]

Answer:

\Delta H=2592.825\ J

Explanation:

The expression for the calculation of the enthalpy change of a process is shown below as:-

\Delta H=m\times C\times \Delta T

Where,  

\Delta H  is the enthalpy change

m is the mass

C is the specific heat capacity

\Delta T  is the temperature change

Thus, given that:-

Mass of object = 36.2 g

Specific heat = 12.5 J/g°C

\Delta T=5.73\ ^0C

So,  

\Delta H=36.2\times 12.5\times 5.73\ J=2592.825\ J

\Delta H=2592.825\ J

7 0
3 years ago
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