Answer:
d.) It is a binary molecular compound.
Explanation:
The compound in question has a formula . The compound is not acidic in nature and the element 'M' is not a metal. This shows that the compound does not contain any metal. Based on the definition of a binary molecular compound as a compound comprising elements that are not metals. Therefore, the compound is obviously a binary molecular compound.
Answer:
The elements in group 13 and group 15 form a cation with a -3 charge each.
That will make a gold-202 nucleus.
<h3>Explanation</h3>
Refer to a periodic table. The atomic number of mercury Hg is 80.
Step One: Bombard the with a neutron . The neutron will add 1 to the mass number 202 of . However, the atomic number will stay the same.
- New mass number: 202 + 1 = 203.
- Atomic number is still 80.
.
Double check the equation:
- Sum of mass number on the left-hand side = 202 + 1 = 203 = Sum of mass number on the right-hand side.
- Sum of atomic number on the left-hand side = 80 = Sum of atomic number on the right-hand side.
Step Two: The nucleus loses a proton . Both the mass number 203 and the atomic number will decrease by 1.
- New mass number: 203 - 1 = 202.
- New atomic number: 80 - 1 = 79.
Refer to a periodic table. What's the element with atomic number 79? Gold Au.
.
Double check the equation:
- Sum of mass number on the left-hand side = 203 = 202 + 1 = Sum of mass number on the right-hand side.
- Sum of atomic number on the left-hand side = 80 = 79 + 1 = Sum of atomic number on the right-hand side.
A gold-202 nucleus is formed.
Answer:
The reactions free energy
Explanation:
From the question we are told that
The pressure of (NO) is
The pressure of (Cl) gas is
The pressure of nitrosly chloride (NOCl) is
The reaction is
⇆
From the reaction we can mathematically evaluate the (Standard state free energy ) as
The Standard state free energy for NO is constant with a value
The Standard state free energy for is constant with a value
The Standard state free energy for is constant with a value
Now substituting this into the equation
The pressure constant is evaluated as
Substituting values
The free energy for this reaction is evaluated as
Where R is gas constant with a value of
T is temperature in K with a given value of
Substituting value
Answer:
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