Calculate the number of molecules in 15.7 mil carbon dioxide

Chemistry

1 answer:

IRISSAK [1]3 years ago

6 0

Answer:

9.45x10^24 molecules

Explanation:

From Avogadro's hypothesis, we understood that 1mole of any substance contains 6.02x10^23 molecules. This suggest that 1mole of CO2 also contains 6.02x10^23 molecules.

Now, if 1mole of CO2 contains 6.02x10^23 molecules, then 15.7moles of CO2 will contain =

15.7 x 6.02x10^23 = 9.45x10^24 molecules

Therefore, 15.7moles of CO2 contains 9.45x10^24 molecules

You might be interested in

The element antimony has an atomic weight of 122 and consists of two stable isotopes antimony-121 and antimony-123. the isotope

grin007 [14]

Answer:- 123 amu.

Solution:- The formula to calculate the average atomic mass of an atom is:

Average atomic mass = mass of first isotope(abundance of first isotope) + mass of second isotope(abundance of second isotope)

Note: The percent abundance is converted to decimals.

mass of Sb-121 is 121 amu and it's percent abundance is 57.3% and in decimal it is 0.573. Percent abundance of Sb-123 is 42.8% and in decimal it is 0.428. We are asked to calculate it's mass. The average atomic mass of Sb is given as 122.

Let's say the mass of Sb-123 is M and plug in the values in the formula and do calculations:

122 = 121(0.573) + M(0.428)

122 = 69.333 + M(0.428)

On rearrangement:-

M(0.428) = 122 - 69.333

M(0.428) = 52.667

$M=\frac{52.667}{0.428}$