All categories

3 years ago

Calculate the number of molecules in 15.7 mil carbon dioxide

Chemistry

1 answer:

IRISSAK [1]3 years ago

6 0

Answer:

9.45x10^24 molecules

Explanation:

From Avogadro's hypothesis, we understood that 1mole of any substance contains 6.02x10^23 molecules. This suggest that 1mole of CO2 also contains 6.02x10^23 molecules.

Now, if 1mole of CO2 contains 6.02x10^23 molecules, then 15.7moles of CO2 will contain =

15.7 x 6.02x10^23 = 9.45x10^24 molecules

Therefore, 15.7moles of CO2 contains 9.45x10^24 molecules

You might be interested in

30cm^3 of a dilute solution of Ca(OH)2 required 11 cm^3 of 0.06 mol/dm^. Hcl for complete neutralization. Calculate the concentr

Alenkasestr [34]

Answer: Thus concentration of $Ca(OH)_2$ in $mol/dm^3$ is 0.011 and in $g/dm^3$ is 0.814

Explanation:

To calculate the concentration of $Ca(OH)_2$ , we use the equation given by neutralization reaction:

$n_1M_1V_1=n_2M_2V_2$

where,

$n_1,M_1\text{ and }V_1$ are the n-factor, molarity and volume of acid which is $HCl$

$n_2,M_2\text{ and }V_2$ are the n-factor, molarity and volume of base which is $Ca(OH)_2$

We are given:

$n_1=1\\M_1=0.06mol/dm^3\\V_1=11cm^3=0.011dm^3\\n_2=2\\M_2=?\\V_2=30cm^3=0.030dm^3$ $1cm^3=0.001dm^3$

Putting values in above equation, we get:

$1\times 0.06mol/dm^3\times 0.011dm^3=2\times M_2\times 0.030dm^3\\\\M_2=0.011mol/dm^3$

The concentration in $g/dm^3$ is $0.011mol/dm^3\times 74g/mol=0.814g/dm^3$

Thus concentration of $Ca(OH)_2$ is $0.011mol/dm^3$ and $0.814g/dm^3$

4 0

3 years ago

Gases with high molecular weights diffuse more slowly than gases with lower molecular weights.

Rom4ik [11]

The answer to this item is TRUE. This can be explained through the Graham's law. This law states that the rate at which gases diffuse is inversely proportional to the square root of their densities which is also related to their molecular masses.

7 0

3 years ago

Read 2 more answers

Coefficients are used in a chemical formula to show the number of each element. True or False

ANTONII [103]

Answer:

The same number of each element present before the reaction takes place must also be present on the product side of the equation. Coefficients are placed in front of a chemical formula to show the number of moles of that substances that are necessary for the reaction to occur.

Explanation:

5 0

3 years ago

Balance NaOH + H3PO4->H2O + Na3PO4

Masteriza [31]

Answer:

3NaOH + H3PO4 ---> 3H2O + Na3PO4

Explanation:

7 0

3 years ago

For the following reaction, 2 SO2(g) + O:(g) 2 SO,(g) the equilibrium constant, K, is 1.32 at 627°C. What is the equilibrium con

cupoosta [38]

Answer:

1.15

Explanation:

2SO₂ + O₂ ⟶ 2SO₃; K =1.32

SO₂ + ½O₂ ⟶ SO₃; K₁ = ?

When you divide an equation by 2, you take the square root of its equilibrium constant.

K₁ = √1.32 = 1.15

The equilibrium constant is 1.15.

8 0

3 years ago