Calculate the number of molecules in 15.7 mil carbon dioxide

Chemistry

1 answer:

IRISSAK [1]2 years ago

6 0

Answer:

9.45x10^24 molecules

Explanation:

From Avogadro's hypothesis, we understood that 1mole of any substance contains 6.02x10^23 molecules. This suggest that 1mole of CO2 also contains 6.02x10^23 molecules.

Now, if 1mole of CO2 contains 6.02x10^23 molecules, then 15.7moles of CO2 will contain =

15.7 x 6.02x10^23 = 9.45x10^24 molecules

Therefore, 15.7moles of CO2 contains 9.45x10^24 molecules

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Answer:

101.4pKa

Explanation:

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How many moles of NH3 would be formed from the complete reaction of 16.0 g H2?

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Taking into account the reaction stoichiometry, 5.33 moles of NH₃ are formed from the complete reaction of 16 grams of H₂.

<h3>Reaction stoichiometry</h3>

In first place, the balanced reaction is:

N₂ + 3 H₂ → 2 NH₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

N₂: 1 mole
H₂: 3 moles
NH₃: 2 moles

The molar mass of the compounds is:

N₂: 14 g/mole
H₂: 2 g/mole
NH₃: 17 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

N₂: 1 mole ×14 g/mole= 14 grams
H₂: 3 moles ×2 g/mole= 6 grams
NH₃: 2 moles ×17 g/mole=34 grams

<h3>Mass of NH₃ formed</h3>

The following rule of three can be applied: if by reaction stoichiometry 6 grams of H₂ form 2 moles of NH₃, 16 grams of H₂ form how many moles of NH₃?

$moles of NH_{3}= \frac{16 grams of H_{2} x2moles of NH_{3}}{6 grams of H_{2}}$