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Elena L [17]
3 years ago
6

(50 points and brainlyest please)

Chemistry
2 answers:
Lorico [155]3 years ago
7 0
I want to say it’s the the first answer, High low tides... I’m pretty sure but I would get a second opinion
Step2247 [10]3 years ago
7 0
The first answer is correct because the gravitational pull of the earth sun and the circled orb in that dark sky with her monthly changes causes high tide and the opposite for low tide
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Burka [1]
I farted it tickled my butt cheeks jingled it was hot it was squishy so I did it again
4 0
3 years ago
Which of the following conclusions might a scientist make when fossils of two different species of very similar organisms are fo
nata0808 [166]

Answer:

if its multiple, C and D, if not, C

Explanation:

brainliesttt?

5 0
3 years ago
(Please help, ASAP) How many grams are in 3.45x10^23 atoms of P?
Daniel [21]

one mole of P weights about 31 grams

in one mole there are 6.022*10^23 atoms

we use the rule of threes

6.022*10^23atoms......weight..........31 grams

3.45*10^23 atoms.........weight...........x grams

x=(3.45*10^23*31)/6.022*10^23

x=106.95/6.022=<u><em>17.76 grams</em></u>

5 0
3 years ago
Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reactionP4(g) + 10 Cl2(g) → 4PCl5(s) ΔH°r
weqwewe [10]

Answer:

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

Explanation:

Enthalpy is denoted by H.

Enthalpy: Total heat change in a chemical reaction is called enthalpy.

The change of entalpy of a reaction is denoted by \bigtriangledown H^\circ_{rxn}

Hass's Law:The change in enthalpy of any process can be determined by calculating the sum of change in enthalpy of each of the steps involved in the process.

g= gas

S= solid

P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}=?

PCl₅(s)→ PCl₃(g)+Cl₂(g) .......(1)       \bigtriangledown H^\circ_{rxn}= +157KJ

P₄(g)+6Cl₂(g)→  4PCl₃(g).............(2)     \bigtriangledown H^\circ_{rxn}= -1207 KJ

If we flip a reaction the value of enthalpy will be change positive to negative or nagative to positive but the numerical value will be remain same.

We need rearrange the equation (1) because in the required equation Cl₂ is on the left side. So we flip the first equation.

PCl₃(g)+Cl₂(g)→PCl₅(s)......(3)          \bigtriangledown H^\circ_{rxn}= -157KJ

Multiplying 4 with equation (3)

4 PCl₃(g)+4Cl₂(g)→4PCl₅(s)......(4)          \bigtriangledown H^\circ_{rxn}=4×( -157)KJ= -628 KJ

Adding equation (2) and (4) we get

P₄(g)+6Cl₂(g)+4 PCl₃(g)+4Cl₂(g)→4PCl₃(g)+4PCl₅(s)    \bigtriangledown H^\circ_{rxn}=( -1207-628)KJ

⇒P₄(g)+10Cl₂(g)→4PCl₃(g)-4PCl₃(g)+4PCl₅(s)      \bigtriangledown H^\circ_{rxn}= - 1835KJ

⇒P₄(g)+10Cl₂(g)→ 4Cl₅(s)       \bigtriangledown H^\circ_{rxn}= -1835 KJ

Therefore  \bigtriangledown H^\circ_{rxn}= -1835 KJ

5 0
3 years ago
How many grams of H2O2 are in 3 moles of H2O2?
stira [4]

Answer:

The answer is 102.3!

Explanation:

you get this by multiplying 34.1 x 3 to get 102.3.

Wondering why you multiply 34.1 times 3?

WELLLLLLLLLLL...

when you get 1 mole of h202, you get 34.1 so if you ask for 3 moles of H202, you get 102.3!

4 0
2 years ago
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