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Ludmilka [50]
3 years ago
12

How do you find the percent yield of a chemical reaction?

Chemistry
2 answers:
kotegsom [21]3 years ago
8 0
To express the efficiency of a reaction, you can calculate the percent yield using this formula: %yield = (actual yield/theoretical yield) x 100. A percent yield of 90% means the reaction was 90% efficient, and 10% of the materials were wasted (they failed to react, or their products were not
Eva8 [605]3 years ago
7 0

Answer:divided and multiple by 100

Explanation:

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How many grams are in 2 moles of Iodine?
Nady [450]

Answer: 253.8

Explanation:

The molar mass of iodine is 126.904. Multiply that by two and you get approximately 253.8 grams in two moles.

6 0
2 years ago
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What is the mass of a 1.71-l sample of a liquid that has a density of 0.921g/ml?
Temka [501]
Hey there!:

Volume in mL :

1.71 L * 1000 => 1710 mL

Density = 0.921 g/mL

Therefore:


Mass = Density * Volume

Mass = 0.921 * 1710

Mass = 1574.91 g
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2 years ago
Molecule A is: A. Isocitrate B. Pyruvate C. Alpha-ketoglutarate D. Oxaloacete E. None of the above
hodyreva [135]

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Explanation:

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2 years ago
How do neutral metal atoms form ions?​
stira [4]

Answer:

Neutral atoms can be turned into positively charged ions by removing one or more electrons. ... Atoms that gain extra electrons become negatively charged. A neutral chlorine atom, for example, contains 17 protons and 17 electrons. By adding one more electron we get a negatively charged Cl- ion with a net charge of -1.

4 0
3 years ago
Gas has a volume of 247.3 ML and is at 100 Celsius and 745 Hg. If the mass of the gas is 0.347 g what is the molar mass of the v
Ahat [919]

Answer:

The molar mass of the vapor is 43.83 g/mol

Explanation:

Given volume of gas = V = 247.3 mL = 0.2473 L

Temperature = T = 100^{\circ}C = 373 K

Pressure of the gas = P = 745 mmHg  (1 atm = 760 mmHg)

P = \displaystyle \frac{745}{760} \textrm{ atm} = 0.9802 \textrm{ atm}

Mass of vapor = 0.347 g

Assuming molar mass of gas to be M g/mol

The ideal gas equation is shown below

\textrm{PV} =\textrm{nRT} \\\textrm{PV} = \displaystyle \frac{m}{M}\textrm{ RT } \\0.98026 \textrm{ atm}\times 0.2473 \textrm{ L} = \displaystyle \frac{3.47 \textrm{ g}}{M}\times 0.0821 \textrm{ L.atm.mol}^{-1}.K^{-1}\times 373\textrm{K} \\M = 43.834 \textrm{ g/mol}

The molar mass of the vapor comes out to be 43.834 g/mol

4 0
2 years ago
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