The given chemical reaction is:
Δ
∑BE(reactants)-∑BE(products)
= {(941 kJ/mol) + (3 * 242 kJ/mol)} -[{2*(3*200 kJ/mol)}]
= 467 kJ/mol
Calculating the change in heat when 85.3 g chlorine reacts in the above reaction:
Moles of chlorine = 
= 1.20 mol 
Heat change when 1.20 mol chlorine reacts
= 
Answer:
One gram helium gas is equal to the 4.002602 g/mole
Explanation:
Helium gas is a gas or chemical element. The symbol of helium gas is He and the atomic number of this gas is 2. This gas is colorless, odorless, and tasteless. It is a non-toxic gas. It is found in the periodic table in the first place.
Helium is a very lightest gas and very abundant in nature in the universe. It is present in the universe around 24 percent. Helium is also called by another name that titan of sun. This is detected by the yellow line. The liquid form of helium gas is called cryogenics. This helium gas is used in lifting balloons and airplanes.
The reaction H2SO4 + 2 NaOH -> Na2SO4 + 2H2O applies to an acid-base titration.
moles NaOH = c · V = 0.2423 mmol/mL · 32.23 mL = 7.809329 mmol
moles H2SO4 = 7.809329 mmol NaOH · 1 mmol H2SO4 / 2 mmol NaOH = 3.9046645 mmol
Hence
[H2SO4]= n/V = 3.9046645 mmol / 37.21 mL = 0.1049 M
The answer to this question is [H2SO4] = 0.1049 M
