Answer:
The concentration of the copper sulfate solution is 83 mM.
Explanation:
The absorbance of a copper sulfate solution can be calculated using Beer-Lambert Law:
A = ε . c . <em>l</em>
where
ε is the extinction coefficient of copper sulfate (ε = 12 M⁻¹.cm⁻¹)
c is its molar concentration (what we are looking for)
l is the pathlength (0.50 cm)
We can use this expression to find the molarity of this solution:

Answer:
437.5 kg of first solution and 812.5 kg of second solution should be mixed to get desired solution.
Explanation:
Let the mass of the first solution be x and second solution be y.
Amount solution required = 1250 kg
x + y = 1250 kg....[1]
Percentage of ethanol in required solution = 12% of 1250 kg
Percentage of ethanol in solution-1 = 5% of x
Percentage of ethanol in required solution = 25% of y
5% of x + 25% of y =12% of 1250 kg

x + 5y = 3000 kg...[2]
Solving [1] and [2] we :
x = 437.5 kg , y = 812.5 kg
437.5 kg of first solution and 812.5 kg of second solution should be mixed to get desired solution.
Explanation:
Since, the given reaction is as follows.
Hence, rate law of the reaction is as follows.
R = ![k[NO][Cl_{2}]](https://tex.z-dn.net/?f=k%5BNO%5D%5BCl_%7B2%7D%5D)
As it is known that rate of a reaction depends on the initial concentration of products. So here, the rate of reaction will depend on the concentration of NO and
. Since, power of the concentrations of each of these is equal to 1. Therefore, order of the reaction is equal to 1 + 1 = 2.
According to the rate law, reactants involved in the rate determining step are NO and
. Hence, first step of the mechanism is the rate determining step.
Also, according to the rate of reaction doubling the concentration of NO will double the rate of reaction.
The number of reactants taking part in a single step of the reaction is known as molecularity of the reaction. Therefore, molecularity of the first step of the reaction is 2.
Both the given steps are not termolecular.
Answer : The mass percentage of isopropyl alcohol in the solution is, 59.4 %
Explanation :
To calculate the mass percentage of isopropyl alcohol in the solution, we use the equation:

Mass of isopropyl alcohol = 6.68 g
Mass of isopropyl alcohol solution = 3.97 g
Putting values in above equation, we get:

Thus, the mass percentage of isopropyl alcohol in the solution is, 59.4 %