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grigory [225]
3 years ago
14

S(s)+3F2(g)->SF6(g) how many mol of F2 are required to react completely with 2.30 mol of S?

Chemistry
1 answer:
Brilliant_brown [7]3 years ago
3 0

Answer:  There are 6.9 mol of F_{2} are required to react completely with 2.30 mol of S.

Explanation:

The given reaction equation is as follows.

S(s) + 3F_{2}(g) \rightarrow SF_{6}(g)

Here, 1 mole of S is reaction with 3 moles of F_{2} which means 1 mole of S requires 3 moles of F_{2}.

Therefore, moles of F_{2} required to react completely with 2.30 moles S are calculated as follows.

1 mol S = 3 mol F_{2}\\2.30 mol S = 3 mol F_{2} \times 2.30 \\= 6.9 mol F_{2}

Thus, we can conclude that there are 6.9 mol of F_{2} are required to react completely with 2.30 mol of S.

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