A half life of 29 years means that after 29 years, only half of this isotope would be left due to radioactive decay. If we start of with 2000g of it and leave it for 116 years, it would undergo 4 "half=lives". 116/29 = 4. So after the first half life, we would have 2000g/2 = 1000g left. After the second, we would have 500g left, after the third, 250g so after 4 half lives or 116 years, there would be 125 g of Strontium-90 left at the site.
The organism was once a clam and most likely became a fossil after being buried by silt in its watery environment after death. Might need more clarification on what exact answer you need.
4 x 6 = 24 because of the coefficient 4 and the subscript 6
Answer:
142.36 kg
Explanation:
volume of water in the lake = surface area x depth
= 18.5 x ( 1760 x 3 )² x 39 ft³
= 2.011 x 10¹⁰ ft³
= 2.011 x 10¹⁰ x 28.3168 liter .
= 56.945 x 10¹⁰ liter .
concentration of mercury = .25 x 10⁻⁶ g / liter
= 25 x 10⁻⁸ g / liter
= 25 x 10⁻¹¹ kg / liter
mass of mercury in the water of lake
= 25 x 10⁻¹¹ x 56.945 x 10¹⁰ kg
= 142.36 kg .
When two bodies interact they apply forces to one another that are equal to magnitude and opposite direction