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2 years ago

I need helpppp plsss

Chemistry

1 answer:

dedylja [7]2 years ago

8 0

Answer:

Blank 1 - 2

Blank 2 - 4

Blank 3 - 3

Explanation:

The unbalanced chemical equation given in the question is as follows:

Au2O3 → Au + O2

To balance a chemical equation, the number of atoms of each element on both sides of the equation (reactants and product) must be the same. Based on this explanation, the balanced chemical equation is as follows:

2Au2O3 → 4Au + 3O2

- 4 atoms of gold (Au) on both sides

- 6 atoms of oxygen on both sides

Hence, based on the question, blank 1, 2 and 3 are 2, 4 and 3 respectively.

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Answer:

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Explanation:

$SO_4^{2-}(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+Sn^{4+}(aq)$

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First we will determine the oxidation and reduction reaction from the givne reaction :

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$Sn^{2+}(aq)\rightarrow Sn^{4+}(aq)$

Balance the charge by adding 2 electrons on product side:

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$SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)$

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$SO_4^{2-}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)$

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$SO_4^{2-}(aq)+4H^+(aq)\rightarrow H_2SO_3(aq)+H_2O(l)$

At last balance the charge by adding electrons on the side where positive charge is more:

$SO_4^{2-}(aq)+4H^+(aq)+2e^-\rightarrow H_2SO_3(aq)+H_2O(l)$ ..[2]

Adding [1] and [2]:

$SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)$

The final balanced equation is :

$SO_4^{2-}(aq)+4H^+(aq)+Sn^{2+}(aq)\rightarrow H_2SO_3(aq)+H_2O(l)+Sn^{4+}(aq)$

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Answer:

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Explanation:

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