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4 years ago

14

Which statement is true about a pseudoscientific idea? It is biased in its results. It can be tested and observed. It can be rep

licated and verified. It is improved with new information.

2 answers:

vesna_86 [32]4 years ago

6 0

<span>It is biased in its results.

</span>

swat324 years ago

5 0

I would say A because I took the same test you did and got it right it’s module one test

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What is the charge of a chlorine ion that has<br> gained 1 electron?

nikdorinn [45]

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4 years ago

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Dna is approximately 2.5 nm in length. of an average man is 5 ft 10 in. tall, how many dna molecules could be stacked to extend

Angelina_Jolie [31]

To determine the number of dna molecules that can be stacked as requested in this item, we convert the given measurements in a single unit. For simplicity, we convert all the lengths to meters.

Length of DNA molecule = (2.5 nm)(1 x 10^-9 m/1 nm) = 2.5 x 10^-9 nm

Height of a person = (5 ft 10 in)(12 inches/ 1ft)(2.54 cm/1 in)(1 x 10^-2 m/ 1 cm)
= 1.778 m

Then, divide the height of the person by the length of a single DNA molecule.

n = 1.778 m / (2.5 x 10^-9)
n = 7.112 x 10^8

Hence, the number of DNA would be 7.112 x 10^9.

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4 years ago

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Calculate the amount in grams of Na2CO3 needed to react with HCL to produce 120g NaCl

worty [1.4K]

Let's start off with the balanced chemical equation:

$Na_2CO_{3_{(s)}} + \textbf2HCl_{_{(aq)}}\rightarrow CO_{2_{(g)}} + H_2O_{_{(l)}} + \textbf2NaCl_{_{(aq)}}$

Assuming the sodium carbonate is the limiting reagent, look at the coefficients of sodium carbonate and sodium chloride and use those as a ratio of sodium carbonate to sodium chloride: 1:2.

Since you have the required mass of NaCl, convert this to moles.

Assuming you know how to find the molar mass of NaCl:

$M_{NaCl} = 58.44g/mol$
$n = \frac{m}{M}$
$n_{NaCl} = \frac{120g}{58.44g/mol}$
$n_{NaCl} = 2.053mol$

Using the ratio, since 1 mole of sodium carbonate is required to produce 2 moles of sodium chloride, cross-multiply the ratios:

$1:2 = x:2.053mol$
$2x = 2.053mol$
$x = 1.027mol$

Therefore 1.027 moles of sodium carbonate is required to produce the required amount of sodium chloride. Convert to mass for your final answer:

$n_{Na_2CO_3} = 1.027mol$
$M_{Na_2CO_3} = 105.99g/mol$
$m = nM$
$m = (1.027mol)(105.99g/mol)$
$m_{Na_2CO_3} = 108.85g$

Hope this helps :)

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3 years ago

Calculate the mass of oxalic acid dihydrate needed to prepare 500.0 ml

VARVARA [1.3K]

Moles= molarity x liter
=0.2500 M x 0.500 L
= 0.1250 mol

mass C2H2O4 . 2H2O = 0.1250 mol x (126.068 g / 1 mol)
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3 years ago

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The reaction of nitrogen gas and oxygen gas to form nitrogen monoxide gas is shown below. If the measured concentrations of all

Anettt [7]

Answer:

The forward reaction is occurring at a faster rate than the reverse reaction.

Explanation:

Reaction quotient (Q) of the given reaction is -

$Q=\frac{[NO]^{2}}{[N_{2}][O_{2}]}$

where [NO], $[N_{2}]$ and $[O_{2}]$ represents concentrations of respective species at a certain time.

Here $[N_{2}]$ = 0.80 M, $[O_{2}]$ = 0.050 M and [NO] = 0.10 M

So, $Q=\frac{(0.10)^{2}}{(0.80)\times (0.050)}=2$

Hence $Q> K$

It means that forward reaction is faster than reverse reaction at that point. Because then only concentration of NO is higher than concentrations of $[N_{2}]$ and $[O_{2}]$ which makes Q higher than K.

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3 years ago