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3 years ago

10

How could you record the number 4000 and report 2 significant figures?

1 answer:

yawa3891 [41]3 years ago

5 0

Explanation:

Write in scientific notation.

4000 = 4.0×10³

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What is an independent variable ?

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A plastic film moves over two drums. During a 4-s interval the speed of the tape is increased uniformly from v0 = 2ft/s to v1 =

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Answer:

Question 1)

a) The speed of the drums is increased from 2 ft/s to 4 ft/s in 4 s. From the below kinematic equations the acceleration of the drums can be determined.

$v_1 = v_0 + at \\4 = 2 + 4a\\a = 0.5~ft/s^2$

This is the linear acceleration of the drums. Since the tape does not slip on the drums, by the rule of rolling without slipping,

$v = \omega R\\a = \alpha R$

where α is the angular acceleration.

In order to continue this question, the radius of the drums should be given.

Let us denote the radius of the drums as R, the angular acceleration of drum B is

α = 0.5/R.

b) The distance travelled by the drums can be found by the following kinematics formula:

$v_1^2 = v_0^2 + 2ax\\4^2 = 2^2 + 2(0.5)x\\x = 12 ft$

One revolution is equal to the circumference of the drum. So, total number of revolutions is

$x / (2\pi R) = 6/(\pi R)$

Question 2)

a) In a rocket propulsion question, the acceleration of the rocket can be found by the following formula:

$a = \frac{dv}{dt} = -\frac{v_{fuel}}{m}\frac{dm}{dt} = -\frac{13000}{2600}25 = 125~ft/s^2$

b) $a = -\frac{v_{fuel}}{m}\frac{dm}{dt} = - \frac{13000}{400}25 = 812.5~ft/s^2$

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3 years ago

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Explanation:

simple

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2 years ago

A volumetric flow rate of 2 m^3/ s of liquid water is to be pumped from sea level to an elevation of 1200 m. Taking the density

exis [7]

Answer:

power requirement is 23.52 × $10^{6}$ W

Explanation:

given data

flow rate q = 2 m³/s

elevation h = 1200 m

density of the water ρ = 1000 kg/m³

to find out

power requirement

solution

we will get power by the power equation that is

power = ρ× Q× g× h ...................1

put here all value we get power

power = ρ× Q× g× h

power = 1000 × 2 × 9.8 × 1200

power = 23.52 × $10^{6}$

so power requirement is 23.52 × $10^{6}$ W

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3 years ago