The key to solve this problem is the conservation of momentum. The momentum of an object is defined as the product between the mass and the velocity, and it's usually labelled with the letter
:

The total momentum is the sum of the momentums. The initial situation is the following:

(it's not written explicitly, but I assume that the 5-kg object is still at the beginning).
So, at the beginning, the total momentum is

At the end, we have

(the mass obviously don't change, the new velocity of the 15-kg object is 1, and the velocity of the 5-kg object is unkown)
After the impact, the total momentum is

Since the momentum is preserved, the initial and final momentum must be the same. Set an equation between the initial and final momentum and solve it for
, and you'll have the final velocity of the 5-kg object.
Answer:
r= 98.3 mm
Explanation:
For rim
R= 0.209 m
M= 4.32 kg
For rods
m= 7.37 kg
L= 2 R= 2 x 0.209 = 0.418 m
The Total moment of inertia of the wagon
I=MR²+2 x 1/12 m L²
Now by putting the values

I=0.413 kg.m²
For disk:
t= 0.0462 m
Density ρ = 5990 kg/m³
Lets take r is the radius of disk
So the mass of the disc
m'=ρ πr² t
The moment of inertia of disc
I'=1/2 m'r²
I'=1/2 x r² x ρ πr² t
Given that
I = I'
1/2 x r² x ρ πr² t = 0.413 kg.m²
1/2 x r³ x ρ π t = 0.413
r³ x ρ π t = 0.826

r³=0.00095
r=0.0983 m
r= 98.3 mm
The mass of Jupitar is obtained from the calculations as 5.8 * 10^-14 Kg.
<h3>What is the mass of Jupitar?</h3>
There are nine planets in the solar system and the sun lies at the enter of our solar system. This is the heliocentric model of the solar system.
Given that;
T^2 = GMr^3/4π
T = period
G = gravitational constant
r = radius
M = mass of Jupitar
Now;
1 day = 86400 seconds
1.77 days = 1.77 days * 86400 seconds/1 day
= 152928 seconds
Making M the subject of the formula;
M =4πT^2/Gr^3
M = 4 * 3.142 * (152928)^2/6.67 × 10^-11 * (422 × 10^9)^3
M = 2.9 * 10^11/5.0 * 10^24
M = 5.8 * 10^-14 Kg
Learn more about mass of a planet:brainly.com/question/13851553
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