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Naily [24]
3 years ago
7

Describe the hypothesis of continental drift.

Chemistry
1 answer:
ludmilkaskok [199]3 years ago
3 0

Answer:

Continental drift was a theory that explained how continents shift position on Earth's surface. It was a prediction look-alike animal and plant fossils, and similar rock formations, are found on different continents.

Explanation:

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A student wants to make a 0.150 M aqueous solution of silver (I) nitrate but only has 11.27 g of AgNO3. What volume of the 0.150
Usimov [2.4K]

Answer:

442.3 mL

Explanation:

Remember that Molarity is a measure of concentration in Chemistry and it's defined as the number of moles of the substance divided by liters of the solution:

M=\frac{Moles of substance X}{Volume of the solution}

Then, you can express 11.27 g of AgNO3 as moles of AgNO3 using the molar mass of the compound:

11.27 g AgNO_{3} *\frac{1 mole AgNO_{3}}{169.87 g AgNO_{3}} = 0.06634 moles AgNO_{3}

Then you can solve for the volume of the solution:

Volume of the solution=\frac{Moles of AgNO_{3}}{M} =\frac{0.06634 mol AgNO_{3}}{0.150 M} =0.4423 L = 442.3 mL

Hope it helps!

3 0
4 years ago
HELP! what's the kPa?
Rus_ich [418]

Answer:

50,662.5 kPa

Explanation:

3 0
3 years ago
1. Do you think that the lightbulb and the Moon spheres are "to scale" compared to the real
Tems11 [23]

Answer:

Yes

Explanation: Had a question like this and I said yes and got it right

3 0
3 years ago
How does a filter separate mixtures like sand and water?​
Talja [164]

Answer:

Filtration is a method for separating an insoluble solid from a liquid. When a mixture of sand and water is filtered: the sand stays behind in the filter paper (it becomes the residue ) the water passes through the filter paper (it becomes the filtrate )

Explanation:

8 0
3 years ago
How many liters of 1.75 M solution could be made using 35 grams of NaCl?
dolphi86 [110]
Data:
M (molarity) = 1.75 M (mol/L)
m (mass) = 35 g
MM (molar Mass) of NaCl = 58.44 g/mol
V (volume) = ? (in liters)

Formula:
M =  \frac{m}{MM*V}

Solving:
M = \frac{m}{MM*V}
1.75 =  \frac{35}{58.44*V}
1.75*58.44V = 35
102.27V = 35
V =  \frac{35}{102.27}
\boxed{\boxed{V \approx 0.34\:L}}\end{array}}\qquad\quad\checkmark
3 0
3 years ago
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