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jeyben [28]
3 years ago
6

Two speakers are spaced 15 m apart and are both producing an identical sound wave. You are standing at a spot as pictured. What

would be the frequency produced by the speakers to create perfectly constructive interference? Assume n = 1 and v = 343 m/s
213.04 Hz
256.70 Hz
186.68 Hz
233.14 Hz
Physics
2 answers:
Alexus [3.1K]3 years ago
7 0

Answer:

The correct answer is option 213.04 Hz

Explanation:

Hello!

Let's solve this!

In this link we will find the image of the problem.

https://smart-answers.com/physics/question14138735

Regarding that image, we will first calculate the distance from my position to S1 and then to S2. Then the difference between these results.

We will use pitagoras.

S1 = \sqrt{10^{2}+22^{2}  }

S1 = 24.17

S2 = \sqrt{5^{2}+22^{2}  }

S2 = 22.56

The difference will be:

24.17-22.56 = 1.61 m

Constructive interference:

Δr=n*λ

λ=1.61 m (for n = 1)

Then we will calculate the frequency:

f = v / λ

f = (343m / s) /1.61m

f = 213.04 Hz

So the correct answer is option 213.04 Hz

e-lub [12.9K]3 years ago
4 0

Answer:

213.04

Explanation:

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A piano tuner is using a 392 Hz tuning fork to tune the wire for a G-Natural note. She hears 4 beats per second. What are the tw
inysia [295]

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