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jeyben [28]
3 years ago
6

Two speakers are spaced 15 m apart and are both producing an identical sound wave. You are standing at a spot as pictured. What

would be the frequency produced by the speakers to create perfectly constructive interference? Assume n = 1 and v = 343 m/s
213.04 Hz
256.70 Hz
186.68 Hz
233.14 Hz
Physics
2 answers:
Alexus [3.1K]3 years ago
7 0

Answer:

The correct answer is option 213.04 Hz

Explanation:

Hello!

Let's solve this!

In this link we will find the image of the problem.

https://smart-answers.com/physics/question14138735

Regarding that image, we will first calculate the distance from my position to S1 and then to S2. Then the difference between these results.

We will use pitagoras.

S1 = \sqrt{10^{2}+22^{2}  }

S1 = 24.17

S2 = \sqrt{5^{2}+22^{2}  }

S2 = 22.56

The difference will be:

24.17-22.56 = 1.61 m

Constructive interference:

Δr=n*λ

λ=1.61 m (for n = 1)

Then we will calculate the frequency:

f = v / λ

f = (343m / s) /1.61m

f = 213.04 Hz

So the correct answer is option 213.04 Hz

e-lub [12.9K]3 years ago
4 0

Answer:

213.04

Explanation:

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The capacitor can withstand a peak voltage of 590 volts. If the voltage source operates at the resonance frequency, what maximum
kirill115 [55]

Answer:

The maximum voltage is 41.92 V.

Explanation:

Given that,

Peak voltage = 590 volts

Suppose in an L-R-C series circuit, the resistance is 400 ohms, the inductance is 0.380 Henry, and the capacitance is 1.20×10^{-2}\ \mu F.

We need to calculate the resonance frequency

Using formula of frequency

f=\dfrac{1}{2\pi\sqrt{LC}}

Put the value into the formula

f=\dfrac{1}{2\pi\sqrt{0.380\times1.20\times10^{-8}}}

f=2356.88\ Hz

We need to calculate the maximum current

Using formula of current

I=\dfrac{V_{c}}{X_{c}}

I=2\pi\times f\times C\times V_{c}

I=2\pi\times2356.88\times1.20\times10^{-8}\times590

I=0.1048\ A

Impedance of the circuit is

z=\sqrt{R^2+(X_{L}^2-X_{C}^2)}

At resonance frequency X_{L}=X_{C}

Z=R

We need to calculate the maximum voltage

Using ohm's law

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V=0.1048\times400

V=41.92\ V

Hence, The maximum voltage is 41.92 V.

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