Two speakers are spaced 15 m apart and are both producing an identical sound wave. You are standing at a spot as pictured. What
2 answers:
Answer:
The correct answer is option 213.04 Hz
Explanation:
Hello!
Let's solve this!
In this link we will find the image of the problem.
https://smart-answers.com/physics/question14138735
Regarding that image, we will first calculate the distance from my position to S1 and then to S2. Then the difference between these results.
We will use pitagoras.
S1 =
S1 = 24.17
S2 =
S2 = 22.56
The difference will be:
24.17-22.56 = 1.61 m
Constructive interference:
Δr=n*λ
λ=1.61 m (for n = 1)
Then we will calculate the frequency:
f = v / λ
f = (343m / s) /1.61m
f = 213.04 Hz
So the correct answer is option 213.04 Hz
You might be interested in
Answer:
W = 1.432 KJ
Explanation:
given,
mass = 22.2 Kg
angle of the rope = 27.5°
distance on the ground = 24 m
kinetic friction= μ = 0.32
acceleration due to gravity, g = 9.8 m/s²
Work done = ?
W = F d cosθ
a = 0 because it is moving with constant speed
equating all the forces acting in x direction
F cosθ = F friction = μN
equating all the forces acting in y direction
F sinθ + N -mg =0
now,
N = mg - F sinθ
putting value of N
F cosθ = μ mg -μ F sinθ
F (cosθ + μsinθ ) = μ mg
F =67.28 N
now,
W=F d cosθ
W =67.28 x 24 x cos(27.5)
W =1432.27 J
W = 1.432 KJ
