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Anvisha [2.4K]
3 years ago
10

12.5% as a fraction in simplest form

Mathematics
1 answer:
love history [14]3 years ago
6 0
12 1/2 i think your welcome
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Need help answering question 4
raketka [301]

Answer:

(-1,5)

Step-by-step explanation:

To find this, you have to add both "x" coordinates, then divide them by two.

Same thing goes for the "y" coordinates, add them, then divide them by two.

x-coordinates --->  2+(-4)= -2

y-coordinates ---> 1+9= 10

-2÷2= -1

10÷2= 5

That gives you, (-1,5).

4 0
3 years ago
5) –2x – 9y=-25<br> -4x – 9y=-23
notka56 [123]

Answer:

(-1,3)

Step-by-step explanation:

–2x – 9y=-25

-4x – 9y=-23

Multiply the second equation by -1

4x + 9y=23

Add this to the first equation

–2x – 9y=-25

4x +  9y= 23

-----------------------

2x        = -2

Divide each side by 2

2x/2 = -2/2

x = -1

Now we need to find y

4x+9y = 23

4(-1) +9y = 23

-4 +9y = 23

Add 4 to each sdie

-4+4 +9y = 23+4

9y = 27

Divide each side by 9

9y/9 = 27/9

y =3

5 0
3 years ago
Read 2 more answers
The graph of a line passes through the points (0,5) and (-10,0). What is the equation
pav-90 [236]

Answer:

Y=1/2x +5

Step-by-step explanation:

(0,5) (-10,0)

0-5/-10-0=1/2

(0,5) (x, y)

Y-5/x-10=1/2(crossmultiply)

2y-10=x

2y= x +10(divide all sides by 2)

Y=1/2x+5

7 0
3 years ago
The South Coast Air Basin (Los Angeles, Orange, and San Bernardino counties) does not meet the air quality standards for carbon
Archy [21]

Answer:

0.2225 gr/mile

Step-by-step explanation:

Let's work out first the amount of CO sent out in 1990.

The population we estimated in 12.5 million people with a total of driven miles per year of about  

12.5 million*8,700 = 108,750 million miles.

With an CO emission factor of 0.9 g per mile, we would have a total of CO emitted rounding 0.9*180,750 = 97,875 million grams

Now, we must estimate the population for 2020.

Since we are assuming an exponential growth, the population in year t is given by a function

\bf P(t)= Ce^{kt}

where C and k are constants to be determined.

We can take 1980 as year 0. This way calculations are lighter. 1990 is year 10 and 2020 is year 20.

So P(0) = 10.3 and C=10.3

So far we have

\bf P(t)= 10.3e^{kt}

Given that P(10)=12.5

\bf 10.3e^{k*10}=12.5\rightarrow e^{10k}=\frac{12.5}{10.3}=1.21359\rightarrow \\10k=log(1.21359)\rightarrow k=0.01936

And the function that models the population growth is

\bf P(t)= 10.3e^{0.01936t}

We need P(20)

\bf P(20)= 10.3e^{0.01936*20}=10.3e^{0.38717}=15.17\;million

If the miles driven per person per year remains constant at 8700 mi/yr.person, then we have a total miles driven of

15.17*8,700=131,979 million miles, so the CO emitted would be 0.9*131,979=118,781.1 million grams.

The 30% of the CO sent out in 1990 is 0.3*97,875=29,362.5 million grams.

We must reduce 118,781.1 down to 29,362.5

Hence the new CO emission factor would be

29,362.5/131,979 = 0.2225 gr/mile

6 0
3 years ago
A certain library assesses fines for overdue books as follows. On the first day that a book is overdue, the total fine is $0.10.
HACTEHA [7]

Answer:

Option B. $0.70

Step-by-step explanation:

First day fine = $0.10

Second day fine (doubled or $0.30 which is lesser)

= $0.10 + $0.10           [$0.10 is lesser than $0.30]

= $0.20

Third day fine = $0.20 + $0.20           [ $0.20 is lesser than $0.30]

                      = $0.40

Fourth day fine = $0.40 + $0.30  = $0.70

[$0.30 is cheaper than doubling the amount $0.40 + $0.40]

Therefore, the total fine for a book on the fourth day is $0.70

4 0
3 years ago
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