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vagabundo [1.1K]
4 years ago
7

Claim: If I brush my teeth everyday, then I won't get cavities.

Chemistry
2 answers:
Olin [163]4 years ago
8 0

Answer:

I wont get cavities it the dependent variable

Explanation:

Rom4ik [11]4 years ago
4 0
The dependent variable is i won’t get cavities
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How many Sodium atoms are in 2.00 mols of Na2O
Anna71 [15]
There’s 1024 atoms of sodium in 2 moles of sodium
7 0
3 years ago
Draw a Lewis structure for ketene, C2H2O , which has a carbon‑carbon double bond. Include all hydrogen atoms and show all unshar
Vladimir79 [104]

<u>Answer:</u> The lewis dot structure is attached below.

<u>Explanation:</u>

A Lewis dot structure is defined as the representation of atoms having electrons around the atom where electrons are represented as dots.

A ketene is an organic compound having general formula R′R″C=C=O, where R and R' are two different/same monovalent chemical groups.

The given chemical compound having formula C_2H_2O is represented as H_2-C=C=O.

Total number of unshared electrons = 4 (left on oxygen atom only)

The lewis dot structure of C_2H_2O is given in the image below.

8 0
3 years ago
One brand of vinegar has a pH of 4.5. Another brand has a pH of 5.0. The equation for the pH of a substance is pH = –log[H+], wh
grigory [225]
[H+] in first brand:
4.5 = -log([H+])
[H+] = 10^(-4.5)

[H+] in second brand:
5 = -log[H+]
[H+] = 10^(-5)

Difference = 10^(-4.5) - 10^(-5)
= 2.2 x 10⁻⁵

The answer is A.
7 0
3 years ago
Read 2 more answers
How many moles are there in 7.5 L Of H2
True [87]
So multiply number of moles x number of atoms/mole = 1.8066 x 10^24 atoms of H2. One mole of any gas at STP has a volume of 22.4 L. So first determine the number of moles of gas you have.
for example do 7
7.5 \div 22.4
that 's what I think
3 0
3 years ago
What is the pH of a 0.08 M solution of Ca(OH),?
torisob [31]

Answer:

pH = 12.20

Explanation:

Ca(OH)2 is a strong base, so it dissociates completely. A 0.08 M solution of Ca(OH)2 is 0.16 M OH-, since every mole of Ca(OH)2 has 2 OH-.

Calculate pOH using [OH-] = 0.16 M

pOH = -log(0.16) = 0.80

pH = 14 - pOH = 14 - 0.80 = 12.20

4 0
3 years ago
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