Answer:
The maximum height reached by the toy rocket is 0.73 meters.
Explanation:
It is given that,
Mass of the toy rocket, m = 0.8 kg
It is projected at an angle of 45 degrees from ground level. The kinetic energy of the rocket is used to find the velocity with which it was projected as :
u = 10.12 m/s
When it reaches to a maximum height, its final velocity will be equal to 0, v = 0
Using third equation of motion to find it as :
a = -g
s is the maximum height reached by the toy rocket
In vertical direction,
s = 0.36 meters
So, the maximum height reached by the toy rocket is 0.73 meters. Hence, this is the required solution.
Answer:
The average velocity of the ball is 1.355 cm/s.
Explanation:
Given;
initial displacement of the ball, x₁ = 8.4 cm
final displacement of the ball, x₂ = 4.2 cm
initial time, t₁ = 3.0 s
final time, t₂ = 6.1 s
The average velocity of the ball is calculated as;
Therefore, the average velocity of the ball is 1.355 cm/s.
Answer:
P = (2 + 3) * V where V is their initial speed (total momentum)
P = 2 * 10 + 3 * Vx where Vx here would be V3
If the initial momentum is not known how can one determine the final velocity of the 3 kg obj.
Also work depends on the sum of the velocities
W (initial) = 1/2 (2 + 3) V^2 the initial kinetic energy
W (final) = 1/2 * 2 * V2^2 + 1/2 * 3 * V3^2
It appears that more information is required for this problem
Answer:
4A
Explanation:
Current is charge per time. So if the second wire delivers twice as much charge in the same amount of time, it must have twice the current.
2 × 2A = 4A