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Helga [31]
3 years ago
14

A mass of 2 kg is hung off a spring,which extends 2 cm determine the energy stored in the spring? ​

Physics
1 answer:
aev [14]3 years ago
3 0
F=kx
2=k*2
2/2=k
1=k

1 J = answer
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Photograph E shows a rechargeable torch. When a student shakes the torch, the magnet moves through the coil and back again. This
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Answer:

a) according to Faraday's law , b) creating a faster movement, placing more turns on coil

Explanation:

a) The voltage is induced in the coil by the relative movement between it and the magnet, therefore according to Faraday's law

           E = - d (B A) / dt

In this case, the magnet is involved, so the value of the magnetic field varies with time, since the number of lines that pass through the loop changes with movement.

This voltage creates a current that charges the battery

b) There are several ways to increase the voltage

* creating a faster movement, can be done by the user

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A skateboarder with a mass of 45 kilograms is riding on a skateboard with a mass of 2.5 kilograms. What should be the velocity o
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What metric unit would you use to estimate the actual distance between Boston and New York?
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Find the current flowing out of the battery.​
klemol [59]

Answer:

0.36 A.

Explanation:

We'll begin by calculating the equivalent resistance between 35 Ω and 20 Ω resistor. This is illustrated below:

Resistor 1 (R₁) = 35 Ω

Resistor 2 (R₂) = 20 Ω

Equivalent Resistance (Rₑq) =?

Since, the two resistors are in parallel connections, their equivalence can be obtained as follow:

Rₑq = (R₁ × R₂) / (R₁ + R₂)

Rₑq = (35 × 20) / (35 + 20)

Rₑq = 700 / 55

Rₑq = 12.73 Ω

Next, we shall determine the total resistance in the circuit. This can be obtained as follow:

Equivalent resistance between 35 Ω and 20 Ω (Rₑq) = 12.73 Ω

Resistor 3 (R₃) = 15 Ω

Total resistance (R) in the circuit =?

R = Rₑq + R₃ (they are in series connection)

R = 12.73 + 15

R = 27.73 Ω

Finally, we shall determine the current. This can be obtained as follow:

Total resistance (R) = 27.73 Ω

Voltage (V) = 10 V

Current (I) =?

V = IR

10 = I × 27.73

Divide both side by 27.73

I = 10 / 27.73

I = 0.36 A

Therefore, the current is 0.36 A.

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