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kaheart [24]
4 years ago
9

A body starts with a velocity of 20 m/s, accelerates uniformly for a time t, moves with constant velocity for the same time, and

finally decelerates to rest, again taking a time t. Given that the final deceleration is three times the original acceleration, and the total distance travelled is 140 m, find t.
Physics
1 answer:
Bezzdna [24]4 years ago
7 0

Answer:

t=0.14s

Explanation:

  • t=
  • <em><u>\frac{s}{v}</u></em>
  • <em><u>t</u></em><em><u>=</u></em>
  • <em><u>\frac{20}{140}</u></em>
  • <em><u>Where</u></em><em><u> </u></em><em><u>s</u></em><em><u>=</u></em><em><u> </u></em><em><u>speed</u></em>
  • <em><u>V</u></em><em><u>=</u></em><em><u>distance</u></em><em><u> </u></em>
  • <em><u>And</u></em><em><u> </u></em><em><u>t</u></em><em><u>=</u></em><em><u>time</u></em><em><u> </u></em>
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