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sashaice [31]
3 years ago
7

When a car stops, the brakes heat up because of friction. What is this an example of?

Physics
1 answer:
Umnica [9.8K]3 years ago
6 0
Kinetic Energy would have to be the answer. Pretty sure.
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Two obiect accumulated a charge of
tamaranim1 [39]

Answer:

A. 181.24 N

Explanation:

The magnitude of hte electrostatic force between two charged objects is given by the equation

F=k\frac{q_1 q_2}{r^2}

where

k is the Coulomb's constant

q1, q2 are the magnitudes of the two charges

r is the separation between the charges

In this problem, we have:

q_1=4.5\mu C=4.5\cdot 10^{-6}C is the magnitude of the 1st charge

q_2=2.8\mu C=2.8\cdot 10^{-6}C is the magnitude of the 2nd charge

r = 2.5 cm = 0.025 m is the separation between the charges

Therefore, the magnitude of the electric force is:

F=\frac{(9\cdot 10^9)(4.5\cdot 10^{-6})(2.8\cdot 10^{-6})}{(0.025)^2}=181.44 N

So, the closest answer is

A) 181.24 N

3 0
4 years ago
The force measuring instrument is called
Phoenix [80]
This instrument is called a spring scale.
5 0
3 years ago
Read 2 more answers
PLEASE Please HELP ME...
cupoosta [38]

Answer:

girl this easy ask yo teacher for help lol

7 0
3 years ago
Work is done on a locked door that remains closed while you try to pull it open. True False.
dsp73

Answer:False

Explanation:

Work is being done on a body when it causes displacement of body on the application of force

Work\ done=Force\times displacement

When we pull the door by a force it causes zero displacements of the door. So we can say that work done on it is zero.

Thus the above-given statement is false  

8 0
4 years ago
(20 points) You are at the center of a boat and have been rowing the boat for a long time. You weigh only 80 kg and your 120 kg
valina [46]

Answer:

Explanation:

From the given information:

Let the first weight be m_ 1 = 80 kg

The weight of the buddy be m_2 = 120 kg

The weight of  Bubba be m_3 = 60 kg

Also, since you and Budda are a distance of 4m to each other, then the length to which both meet buddy will be:

x_1 = x_3 = \dfrac{4}{2} \\ \\ = 2

The length of the boat be x_2 = 4 m

∴

We can find the center of mass of the system by using the formula:

X_{CM} = \dfrac{m_1x_1+m_2x_2+m_3x_3}{m_1+m_2+m_3} \\ \\ X_{CM} = \dfrac{(80 \times 2)+(120\times4)+(60\times2)}{80+120+60} \\ \\ X_{CM} = \dfrac{160+480+120}{260} \\ \\ \mathbf{X_{CM} = 2.923}

4 0
3 years ago
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