When a car stops, the brakes heat up because of friction. What is this an example of?

18. Write conversion factors (as ratios) for the number of:

Romashka [77]

Answer:

Conversion tables show:

1 m = 1.09361 yds

1 Lit = .26418 gal = 1.05672 qt or 1 qt = .944632 Lit

1 lb = .45359 kg = 2.2046 Lbs / Kg

So X yds = X m * 1.09361 yds / m = 1.09361 * X yds

Likewise X Lit = X qt / 1.05672 qt/ Lit = X / 1.05672 Lit = .94632 X Lit

So X Lbs = X kg * 2.2046 Lbs / Kg = 2.2046 Lbs

6 0

3 years ago

Burl the painter weighs 600 Newtons. He stands in the exact middle of his stage. There are two scale readings attached to the tw

chubhunter [2.5K]

Answer:

T = 300 N

Explanation:

As we know that the painter is standing at the middle of the scaffold

So here the two ropes will exert same tension on the scaffold

So we will have

$T_1 + T_2 = W$

also we know

$T_1 = T_2$

so we will have

$2T = W$

$T = \frac{W}{2}$

so tension is half of the weight in both the strings

So it is

T = 300 N

6 0

3 years ago

The greatest ocean depths on the earth are found in the marianas trench near the philippines. calculate the pressure due to the

tensa zangetsu [6.8K]

First, let us derive our working equation. We all know that pressure is the force exerted on an area of space. In equation, that would be: P = F/A. From Newton's Law of Second Motion, force is equal to the product of mass and gravity: F = mg. So, we can substitute F to the first equation so that it becomes, P = mg/A. Now, pressure can also be determined as the force exerted by a fluid on an area. This fluid can be measure in terms of volume. Relating volume and mass, we use the parameter of density: ρ = m/V. Simplifying further in terms of height, Volume is the product of the cross-sectional area and the height. So, V = A*h. The working equation will then be derived to be:

P = ρgh

This type of pressure is called the hydrostatic pressure, the pressure exerted by the fluid over a known height. Next, we find the literature data of the density of seawater. From studies, seawater has a density ranging from 1,020 to 1,030 kg/m³. Let's just use 1,020 kg/m³. Substituting the values and making sure that the units are consistent:

P = (1,020 kg/m³)(9.81 m/s²)(11 km)*(1,000 m/1km)
P = 110,068,200 Pa or 110.07 MPa

6 0

3 years ago

A pendulum is formed by taking a 2.0 kg mass and hanging it from the ceiling using a steel wire with a diameter of 1.1 mm. it is

Lera25 [3.4K]

Answer: 1.39 s

Explanation:

We can solve this problem with the following equations:

$\frac{\Delta l}{l_{o}}=\frac{F}{AY}$ (1)