What is the factorization of the polynomial below?

Hepl...<br>I will mark as brainliest

Law Incorporation [45]

Answer:

a) -9, -5, 2, 3

b) 1.66, 0,33, -1.55, -3.25

c) -4.01, -3.35, 0.35, 0.81

Step-by-step explanation:

8 0

3 years ago

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A hospital recorded the weight of babies born at the hospital during one week on a line plot. How many more pounds was the baby

lbvjy [14]

greatest weight 20 lowest weight 5

3 0

2 years ago

Calculate the area of the shaded region between the regular polygons. Round to the nearest hundredth.

wolverine [178]

Answer:

I hope I'll help you with this but I am not sure of it all...

The area of the shaded region is 46,77

Step-by-step explanation:

To determine the area of the shaded hexagon, we must first calculate te area of the whole shaded hexagon and minus that by the white little hexagon.

The formula to calculate the area of a hexagon is (3√3 s2)/ 2

(where s = one side of the hexagon)

if one side a the little white hexagon equals 6 ft;

3√3 6ft.2/2 = 18√3/2 = 9√3

now for the bigger hexagon where one side is 12 ft;

3√3 12 ft.2/2 = 72√3/2 = 36√3

now the area of the bigger one minus the area of the smaller one;

36√3 - 9√3 = 46,77

3 0

2 years ago

Read the following bar graph and answer the following related questions :

Varvara68 [4.7K]

apala
meenu
1:2
4 girls..

3 0

2 years ago

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Let the following sample of 8 observations be drawn from a normal population with unknown mean and standard deviation:

Vikentia [17]

Answer:

a

$\= x = 18.5$ , $\sigma = 5.15$

b

$15.505 < \mu < 21.495$

c

$14.93 < \mu < 22.069$

Step-by-step explanation:

From the question we are are told that

The sample data is 21, 14, 13, 24, 17, 22, 25, 12

The sample size is n = 8

Generally the ample mean is evaluated as

$\= x = \frac{\sum x }{n}$

$\= x = \frac{ 21 + 14 + 13 + 24 + 17 + 22+ 25 + 12 }{8}$

$\= x = 18.5$

Generally the standard deviation is mathematically evaluated as

$\sigma = \sqrt{\frac{\sum (x- \=x )^2}{n}}$

$\sigma = \sqrt{\frac{\sum ((21 - 18.5)^2 + (14-18.5)^2+ (13-18.5)^2+ (24-18.5)^2+ (17-18.5)^2+ (22-18.5)^2+ (25-18.5)^2+ (12 -18.5)^2 )}{8}}$

$\sigma = 5.15$

considering part b

Given that the confidence level is 90% then the significance level is evaluated as

$\alpha = 100-90$

$\alpha = 10\%$

$\alpha = 0.10$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.645$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.645 * \frac{5.15 }{\sqrt{8} }$

=> $E = 2.995$

The 90% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 2.995 < \mu < 18.5 + 2.995$

$15.505 < \mu < 21.495$

considering part c

Given that the confidence level is 95% then the significance level is evaluated as

$\alpha = 100-95$

$\alpha = 5\%$

$\alpha = 0.05$

Next we obtain the critical value of $\frac{ \alpha }{2}$ from the normal distribution table the value is

$Z_{\frac{ \alpha }{2} } = 1.96$

The margin of error is mathematically represented as

$E = Z_{\frac{ \alpha }{2} } * \frac{\sigma }{\sqrt{n} }$

=> $E =1.96 * \frac{5.15 }{\sqrt{8} }$

=> $E = 3.569$

The 95% confidence interval is evaluated as

$\= x - E < \mu < \= x + E$

substituting values

$18.5 - 3.569 < \mu < 18.5 + 3.569$

$14.93 < \mu < 22.069$

8 0

2 years ago