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Sedbober [7]
3 years ago
15

HELP ASAP-WILL GIVE BRAINLIEST-NO FILES

Physics
1 answer:
xxMikexx [17]3 years ago
4 0

Answer:C

Explanation:

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A 3250 N car is pushed a distance of 35 m the power was 11375 J, how long did it take?
irakobra [83]

Answer:

10.8s

Explanation:

Given parameters:

Force on the car  = 3250N

Distance  = 35m

Power  = 11375W

Unknown:

Time taken = ?

Solution:

To solve this problem;

 Power is the rate at which work is done

         Power = \frac{work done }{time}  

  Work done  = force x distance  = 3250 x 35  = 123200J

Now;

          11375  = \frac{123200}{t}  

           11375t  = 123200  

                   t  = 10.8s

5 0
3 years ago
What is the average acceleration during the time interval 0 seconds to 10 seconds?
Hunter-Best [27]

Answer:

yea its D  .

Explanation:

3 0
3 years ago
A soccer player is running upfield at 10m/s and comes to a stop in 3 seconds facing the same direction. What is his acceleration
Mekhanik [1.2K]
The players acceleration is 3.33 m/s/s

Acceleration= Velocity/Time

A =10/3
4 0
3 years ago
Read 2 more answers
Write down applications of mechanics​
harkovskaia [24]

Answer:

Explanation:

applied Mechanics and its Growing Utilisation of Theoretical Mechanics.\

Structural Engineering.

Hydraulics.  

Mechanical Engineering.  

External Fluid Dynamics.

Planetary Sciences.

Life Sciences.

7 0
3 years ago
ALWAYS use significant figure rules. Remember that these rules apply to all numbers that are measurements. A person walks along
Elza [17]
To find the total number of miles traveled by a person, we add the distance that he has traveled: 3.0 + 5.00 + 4.000. 

Now, to find the accurate number of significant figures when adding measurements, the basic rule for addition is to use the least number of decimal places when reporting the result.

Now, since 3.0 has the least number of decimal places, we report the sum with 1 decimal place and have 12.0 miles as the total distance traveled by the person to reach his destination.

Answer: 12.0 miles
8 0
3 years ago
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