Answer:
Part a)
W = 16.7 N
Part b)
r = 2.45 R
Explanation:
Part a)
As we know that acceleration due to gravity on the surface of moon is 1/6 times the gravity on the surface of earth
So the force due to gravity will decrease by the factor of 6
so we will have
Part b)
For the same value of the weight as the surface of moon the acceleration due to gravity of earth must be 1/6 times
so we have
Answer:
Acceleration is the change in velocity over the change in time = Δv/Δt. To do these problems, you need to find out how much the speed changed and over what period of time it changed.
Snail 1 changes from 4 cm/min to 7 cm/min in 3 minutes. Subtract the starting velocity (4 cm/min) from the ending velocity (7 cm/min) then divide by the time (3 min):
Snail 1 = (7 cm/min. - 4 cm/min)/(3 minutes) = ? (remember to put down the units)
Snail 2 changed from 7 cm/min. down to 1 cm/min. in 3 minutes
Snail 2 = (1 cm/min. - 7 cm/min.)/(3 min.) = ? (note that the acceleration is negative when you slow down)
I hope this helps you
2.85 x 10^2 (ten to the second power)
There's no such thing as an "average marathon". The marathon run is a world athletic sport in which records are kept, and every marathon is the same distance. The official distance of The Marathon is 42.195 km.
Time = (distance covered) / (average speed).
Time = (42.195 km) / (2.57 m/s) = 16,418.29 seconds
= 4hrs 33min 38.29 sec
Note:
With no information given regarding the direction of any part of the
course, the solution must proceed in terms of speed, not velocity.
The question is written as if 'velocity' were a more formal, technical
word for 'speed', but such is not the case. They are two different
things.
A foot race is a very awkward place to attempt a discussion in terms
of velocity. On a typical marathon course, the starting line and finish line
are in the same place. Where that is true, the displacement of a runner
who completes the course is zero, and his average velocity is also zero.
Knowing the magnitude of the initial velocity and the magnitude of the final velocity of a body, we can calculate its average acceleration if we know how much time elapsed in the change of velocity.
So:
a = Δv / Δt
a = (v2-v1) / t2-t1
a = (15-7) / 2
a = 8/2
a = 4m / s²
Finally the average acceleration with which it moves is 4m / s²