Answer:
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Explanation:
Answer:
The displacement of the car after 6s is 43.2 m
Explanation:
Given;
velocity of the car, v = 12 m/s
acceleration of the car, a = -1.6 m/s² (backward acceleration)
time of motion, t = 6 s
The displacement of the car after 6s is given by the following kinematic equation;
d = ut + ¹/₂at²
d = (12 x 6) + ¹/₂(-1.6)(6)²
d = 72 - 28.8
d = 43.2 m
Therefore, the displacement of the car after 6s is 43.2 m
Answer:

Explanation:
given,
scattering angle of alpha particle = 25.0° above its initial direction of motion
oxygen nucleus recoils at = 50.0° below this initial direction.
final speed of the oxygen = 2.08×10⁵ m/s
mass of alpha particle = 4.0 u
mass o oxygen nucleus = 16 u
momentum conservation along x- axis


....(1)
Along y-direction




putting value in equation (1)


Answer:
New length = 10.2 m
Explanation:
Let ΔL = change in length
ΔT = change in the temperature
L(0) = intial length
α = coeffient of linear expansion
Then
ΔL = αL(0)ΔT
=(2.4×10^-5)(10)(100-20)
=0.0192 m
New length = L(0) + ΔL
= 10 + 0.0192
= 10.2 m