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Art [367]
2 years ago
12

Find the equation of the circle if one of the endpoints of the diameter is (-2,-3) and the midpoint of the circle's diameter is

(4,5).
Mathematics
1 answer:
tankabanditka [31]2 years ago
8 0

Answer:

The answer to your question is    (x - 4)² + (y - 5)² = 100

Step-by-step explanation:

Data

Point = (-2, -3)

Midpoint = (4, 5)

Process

1.- Find the length of the radius using the formula of the distance between two points.

dPM = \sqrt{(x2 - x1)^{2}+ (y2 - y1)^{2}}

x1 = -2   y1 = -3   x2 = 4   y2 = 5

dPM = \sqrt{(4 + 2)^{2} + (5 + 3)^{2}}

dPM = \sqrt{(6)^{2} + (8)^{2}}

dPM = \sqrt{36 + 64}

dPM = \sqrt{100}

dPM = 10

2.- Find the equation of the line

                  (x - h)² + (y - k)² = r²

h = 4

k = 5

r = 10

                 (x - 4)² + (y - 5)² = 10²

                 (x - 4)² + (y - 5)² = 100

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The vertices of quadrilateral MNPQ are M(−3,−2),N(−1,4),P(2,4), and Q(4,−2). Translate quadrilateral MNPQ using the vector ⟨3,−4
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Answer:

see explanation

Step-by-step explanation:

A translation using the vector < 3, - 4 > , means

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2 years ago
7x - 20 = 2x - 3(3x + 2)
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Answer:

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We move all terms to the left:

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We calculate terms in parentheses: -(2x-3(3x+2)), so:

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We multiply parentheses

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We add all the numbers together, and all the variables

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Back to the equation:

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We get rid of parentheses

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Step-by-step explanation:

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Your equation is a little messed up comment me the equation you need help with
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