1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ugo [173]
3 years ago
5

A baseball player swings at a baseball of m = 0.23 kg. The force exerted on the ball by the bat is 5.0 N forward. What is the fo

rce of the ball on the bat? 22 N backwards 22 N forwards 5 N forwards 5 N backwards
Physics
2 answers:
Jlenok [28]3 years ago
5 0
5 N backwards because it exerts an equal and opposite force
Nimfa-mama [501]3 years ago
3 0

Answer:

5 N backwards

Explanation:

As we know that as per Newton's III law every action has equal and opposite reaction force.

So if we applied an action force on an object then that object will apply equal force but opposite in direction on us

So here we know that bat exert a forward force on the ball which is of magnitude 5 N

so as per Newton's III law the ball must exert same force of same magnitude in opposite direction on bat

So here force applied by ball will be

F = 5 N backwards

You might be interested in
Explain why radiation is dangerous to humans
tia_tia [17]
Radiation damages the cells that make up the human body, it can even cause cancer
7 0
3 years ago
Read 2 more answers
Five race cars speed toward the finish line at the Jasper County Speedway. The table lists each car’s speed in meters/second. If
Anarel [89]
I think the answer would be Car C.
7 0
3 years ago
Read 2 more answers
Spidermans nemesis electro delivers 4kj of electrical energy in half a second how much power does it draw from the mains?
Elodia [21]

Power delivered = (energy delivered) / (time to deliver the energy)

Power delivered = (4,000 J) / (0.5 sec)

Power delivered = 8,000 watts

I'm a little surprised to learn that Electro draws his power from the mains.  This is VERY good news for Spiderman !  It means that Spiderman can always avoid tangling with Electro ... all he has to do is stay farther away from Electro than the length of Electro's extension cord.

But OK.  Let's assume that Electro draws it all from the mains.  Then inevitably, there must be some loss in Electro's conversion process, between the outlet and his fingertips (or wherever he shoots his bolts from).

The efficiency of Electro's internal process is

<em>(power he shoots out) / (power he draws from the mains) </em>.

So, if he delivers energy toward his target at the rate of 8,000 watts, he must draw power from the mains at the rate of

<em>(8,000 watts) / (his internal efficiency) .  </em>

4 0
3 years ago
Read 2 more answers
A man stands on a platform that is rotating (without friction) with an angular speed of 1.0 rev/s; his arms are outstretched and
Airida [17]

Answer:

Explanation:

Given

N_1=1 rev/s

angular velocity \omega =2\pi N_1=6.284 rad/s

Combined moment of inertia of stool,student and bricks =6\ kg.m^2

Now student pull off his hands so as to increase its speed to suppose N_2 rev/s

\omega _2=2\pi N_2  

After Pulling off hands so final moment of inertia is

I_2=2\ kg-m^2

Conserving angular momentum  as no external torque is applied

I_1\omega _1=I_2\omega _2

6\times 6.284=2\times \omega _2

\omega _2=18.85\ rad/s

N_2=3 rev/s

7 0
3 years ago
A chinook salmon needs to jump a waterfall that is 1.5 m high. If the fish starts from a distance of 1.00 m from the base of the
____ [38]
 <span>let the fsh jump with initial velocity (u) in direction (angle p) with horizontal 

it can cross and reach top of trajectory if its top height h = 1.5m 
and horizontal distance d = (1/2) Range 
--------------------------------------... 
let t be top height time 
at top height, vertical component of its velocity =0 
vy = 0 = u sin p - gt 
t = u sin p/g 
h = [u sin p]*t - 0.5 g[t[^2 
1.5 = u^2 sin^2 p/g - u^2 sin^2 p/2g 
u^2 sin^2 p/2g = 1.5 
u^2 sin^2 p = 1.5*2*9.8 = 29.4 
u sin p = 5.42 m/s >>>>>>>>>>>>>>> V-component 
===================== 
t = HALF the time of flight 
d = (1/2) Range (R) = (1/2) [2 u^2 sin p cos p/g] 
1 = u^2 sin p cos p/g 
u sin p * u cos p = 9.8 
5.42 * u cos p = 9.8 
u cos p = 1.81 m/s >>>>>>>>>>>>> H-component 
check>> 
u = sqrt[u^2 cos^2 p + u^2 sin^2 p] = 5.71 m/s 
u < less than fish's potential jump speed 6.26 m/s 

so it will able to cross</span>
8 0
3 years ago
Other questions:
  • How do rocks within Earth change as P waves pass? How do rocks within Earth change as P waves pass? Rocks within Earth both expa
    6·1 answer
  • You are given a long length of string and an oscillator that can shake one end of the string at any desired freqeuency
    6·1 answer
  • Jayne lifts the barbell 120 cm upwards. She has a mass of 60kg. How much work does she do?
    7·1 answer
  • How do you the average speed
    15·1 answer
  • Are graded receptor potentials always depolarizing? Do graded receptor potentials always make it easier to induce action potenti
    7·1 answer
  • An electrostatic dust precipitator that is installed in a factory smokestack includes a straight metal wire of length 0.7 m that
    8·1 answer
  • What is machine. what is mechanica advantage​
    5·2 answers
  • The scientist who suggested that energy can be created under certain conditions was
    8·1 answer
  • Problem 2: (15 pts) A 10-m high cylindrical container is half-filled at the bottom with water of density =1000 kg/m3 while the t
    10·2 answers
  • Help now WILL MARK BRAINLEST
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!