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trasher [3.6K]
3 years ago
8

Use the periodic table to determine which elements are likely to have a larger atomic radius than silicon (Si). Check all that a

pply.
aluminum (Al)
carbon (C)
sulfur (S)
tin (Sn)
Chemistry
2 answers:
algol133 years ago
8 0

<u><em>Answer</em></u>

  • aluminum (Al)  
  • tin (Sn)

<u><em>Explanation</em></u>

1. aluminum (Al)

  • Al has large atomic radius than Si because in periodic table atomic radius decreases from left to right, as Al is present 3A group while Si is present in 4A.

2. carbon (C)

  • C has small atomic radius than Si because in periodic table, atomic radius increases down the group, as both C and Si are present in same group, C is present at Top while Si at bottom.

3. sulfur (S).

  • S has small atomic radius than Si because in periodic table atomic radius decreases from left to right, as S is present 6A group while Si is present in 4A.

4. tin (Sn)

  • Tin has large atomic radius than Si because in periodic table, atomic radius increases down the group, as both Tin and Si are present in same group, Si is present at Top while Tin at bottom.
frozen [14]3 years ago
8 0

Use the periodic table to determine which elements are likely to have a larger atomic radius than silicon (Si). Check all that apply.


aluminum (Al)

tin (Sn)

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Two solutions, initially at 24.60 °C, are mixed in a coffee cup calorimeter (Ccal = 15.5 J/°C). When a 100.0 mL volume of 0.100
yulyashka [42]

Answer:

ΔH = -59.6kJ/mol

Explanation:

The reaction that occurs between Ag⁺ and Cl⁻ ions is:

Ag⁺ + Cl⁻ → AgCl(s) + ΔH

To find ΔH we need to obtain moles of reaction and heat released in the reaction because ΔH is defined as heat released per mole of reaction.

<em>Moles of reaction:</em>

Moles of Ag⁺ and Cl⁻ added are:

Ag⁺: 0.100L * (0.100mol / L) = 0.01moles

Cl⁻: 0.100L * (0.200mol / L) 0 0.02 moles

That means limiting reactant is Ag⁺ and moles of reaction are 0.01 moles

<em>Heat released:</em>

To find heat released we must use coffe cup calorimeter equation:

Q = C*m*ΔT

<em>Where C is specific heat of solution (4.18J/g°C), m is the mass of solution (200g because there are 100 + 100mL = 200mL and density of solution is 1g/mL) and ΔT is change in temperature (25.30°C - 24.60°C = 0.70°C).</em>

Replacing:

Q = C*m*ΔT

Q = 4.18J/g°C * 200g * 0.70°C

Q = 585,2J

Is total heat released.

The calorimeter absorbs:

15.5J / °C * 0.7°C = 10.85

Thus, when 0.01 moles reacts, 585.2J + 10.85  = 596.05J are released (Heat released is heat abosrbed by calorimeter + Heat absorbed by water) and ΔH is:

ΔH = 596.05J / 0.01 moles =

ΔH = 59605J / mol =

<h3>ΔH = -59.6kJ/mol</h3>

<em>As heat is released, ΔH < 0.</em>

6 0
3 years ago
0.023 M solution of perchloric acid
kogti [31]
The original question is to find the pH and the pOH of 0.023 M of perchloric acid.

Answer:
pH = 1.638
pOH = 12.362

Explanation:
1- getting the pH:
pH can be calculated using the following rule:
pH = -log[H+]
Since the given solution is an acid, this means that [H+] is the same as the concentration of the solution.
This means that:
[H+] = 0.023
Substitute in the above equation to get the pH as follows:
pH = -log[0.023]
pH = 1.638

2- getting the pOH:
We know that:
pH + pOH = 14
We have calculated that pH = 1.638.
Substitute in the above equation to get the pOH as follows:
pOH + 1.638 = 14
pOH = 14 - 1.638
pOH = 12.362

Hope this helps :)
5 0
3 years ago
One difference between mixtures and pure substances is that
defon

Answer:

The mixture is made up of different atoms and pure substance is made up of same type of atom.

The main difference is that mixture can be separated into its component by physical mean while pure substances can not be separated by physical process

Explanation:

Mixture:

  • The properties of the mixture are not same and contains the properties of all those component present in it.
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Examples are:

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  • Salt water is mixture of water and NaCl and can be separated by physical mean.
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Pure Substance:

Pure substances are those made of same type of atoms all elements and compounds are pure substances.

  • it can not be separated by simple physical mean
  • it have very constant and consistent melting and boiling point

Examples are:

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  • All compounds: can not be separated by physical mean.

8 0
3 years ago
Read 2 more answers
2. HOW MUCH HEAT IS REQUIRED TO BE RELEASED WHEN
jarptica [38.1K]

Answer: -112200J

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Thus, Q = MCΦ

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Q = ?

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C = 187 J/ G°C

Φ = (Final temperature - Initial temperature)

= 100°C - 120°C = -20°C

Then apply the formula, Q = MCΦ

Q = 30.0g x 187 J/ G°C x -20°C

Q = -112200J (The negative sign does indicates that heat was released to the surroundings)

Thus, -112200 joules of heat is released when cooling the superheated vapour.

5 0
3 years ago
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Salsk061 [2.6K]
The N2H4 bond angle will be probably 109 degrees. Since, well,<span> it has a bent </span>trigonal pyramidal<span> geometry.</span>
8 0
3 years ago
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