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trasher [3.6K]
4 years ago
8

Use the periodic table to determine which elements are likely to have a larger atomic radius than silicon (Si). Check all that a

pply.
aluminum (Al)
carbon (C)
sulfur (S)
tin (Sn)
Chemistry
2 answers:
algol134 years ago
8 0

<u><em>Answer</em></u>

  • aluminum (Al)  
  • tin (Sn)

<u><em>Explanation</em></u>

1. aluminum (Al)

  • Al has large atomic radius than Si because in periodic table atomic radius decreases from left to right, as Al is present 3A group while Si is present in 4A.

2. carbon (C)

  • C has small atomic radius than Si because in periodic table, atomic radius increases down the group, as both C and Si are present in same group, C is present at Top while Si at bottom.

3. sulfur (S).

  • S has small atomic radius than Si because in periodic table atomic radius decreases from left to right, as S is present 6A group while Si is present in 4A.

4. tin (Sn)

  • Tin has large atomic radius than Si because in periodic table, atomic radius increases down the group, as both Tin and Si are present in same group, Si is present at Top while Tin at bottom.
frozen [14]4 years ago
8 0

Use the periodic table to determine which elements are likely to have a larger atomic radius than silicon (Si). Check all that apply.


aluminum (Al)

tin (Sn)

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Answer:

m = 0.659 ounce

Explanation:

It is given that,

The thickness of a Teflon coating is, d = 1 mm

Area of the coating, A = 36 inch²

The density of Teflon, d = 0.805 g/mL

We need to find ounces of Teflon are needed.

Firstly, find the volume of the Teflon needed,

1 inch² = 6.4516 cm²

36 inch² = 232.258 cm²

Density,

\rho=\dfrac{m}{V}

V is volume of the Teflon needed, V = Ad

So,

m=\rho V\\\\m=0.805\ g/cm^3\times 232.258\ cm^2 \times 0.1\ cm\\\\m=18.69\ g

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3 0
3 years ago
For the reaction shown, calculate how many moles of NH3 form when 16.72 moles of reactant completely reacts:
Agata [3.3K]

Answer : The moles of NH_3 formed are, 22.3 moles.

Explanation : Given,

Moles of N_2H_4 = 16.72 mol

The given chemical reaction is:

3N_2H_4(l)\rightarrow 4NH_3(g)+2N_2(g)

From the balanced chemical reaction, we conclude that:

As, 3 moles of N_2H_4 react to give 4 moles of NH_3

So, 16.72 moles of N_2H_4 react to give \frac{4}{3}\times 16.72=22.3 moles of NH_3

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3 years ago
How many liters of hydrogen gas are formed from the complete reaction of 1.03 mol of C? Assume that the hydrogen gas is collecte
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27 liters of hydrogen gas will be formed

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Step 1: Data given

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Pressure H2 = 1.0 atm

Temperature = 319 K

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C +H20 → CO + H2

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For 1 mol C we need 1 mol H2O to produce 1 mol CO an 1 mol H2

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⇒with V = the volume of H2 gas = TO BE DETERMINED

⇒with n = the number of moles H2 gas = 1.03 moles

⇒with R = the gas constant = 0.08206 L*Atm/mol*K

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V = (n*R*T)/p

V = (1.03 * 0.08206 *319) / 1

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