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Shalnov [3]
4 years ago
8

When the displacement of a mass on a spring is 12 a the half of the amplitude, what fraction of the mechanical energy is kinetic

energy?
Physics
1 answer:
Sveta_85 [38]4 years ago
7 0
You know that when the displacement is equal to the amplitude (A), the velocity is zero, which implies that the kinetic energy (KE) is zeero, so the total mechanical energy (ME) is the potential energy (PE).

And you know that the potential energy, PE, is [ 1/2 ] k (x^2)

Then, use x = A, to calculate the PE in the point where ME = PE.

ME = PE = [1/2] k (A)^2.

At half of the amplitude, x = A/2 => PE = [ 1/2] k (A/2)^2

=> PE = [1/4] { [1/2]k(A)^2 } = .[1/4] ME

So, if PE is 1/4 of ME, KE is 3/4 of ME.

And the answer is 3/4


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A battery connected to two wires in parallel. Both wires are made of the same material and are of the same length, but the diame
Free_Kalibri [48]

Answer:

true  1

2 is false   2. 3 . 4. 5  

Explanation:

For this exercise, let's calculate the different parameters and analyze the corresponding statements.

the resistance of each wire

         R = ρ \frac{L}{A}

wire B.

has a diameter of d₀

therefore its radius is r₀ = d₀ / 2

the area is A = pi r₀²

                     A = π d₀²/ 4

we subtitle

          Ro = ρ \frac{L \ 4}{\pi  d_o^2}

          R_b = R₀

wire A

the diameter is d = 2d₀

therefore the radius is r = d/2

                        r = d₀

resistance is

              R_a = ρ \frac{L}{\pi  d_o}

   

              R_a = 4 R₀

when examining the answers

1 is true

4 is false

Now let's calculate the power

         P = V I

         V = I R

         P = V² / R

as they indicate that the cables are connected in parallel, the voltage in them is the same, therefore the potency depends on the resistance

         

wire B  

         P = V² / R_b

          P_b = V² / R₀

wire A

          P_a = v² / R_a

          P_a = V² / 4R₀

          P_a = ¼ P_b

2 is false

in a parallel circuit the waves are the same therefore

3 False

ohm's law is

         V = I r

         I = V / R

   

wire B

       I_b = V / R_b

       I_b = V / Ro

wire

       I_a = V / R_a

       I_a = V / 4 Ro

       I_a = ¼ I_a

5 is false

6 0
3 years ago
(For example, if you used a lunch meat that claimed to be 97% fat-free, were just 3% of its calories provided by fat?) If the ma
klasskru [66]

The difference between the manufacturer's claims and your findings is, the manufacturer is concerned about amount of fat in the meat while you are concerned about calories.

<h3>Difference between your findings and the manufacturers claim</h3>

Your findings concluded that only fat can provide calories needed in the body, perhaps other classes of food or nutrients in the meat can provide calories as well.

In the manufacturer's claim there are about 3% fat in the lunch meat and doesn't necessary mean that all the calories needed is the 3% fat.

Thus, there are lots of difference between your findings and the manufacturer's claim. The manufacturer is concerned about amount of fat in the lunch meat while you are concerned about calories in the meat.

Learn more about claims here: brainly.com/question/2748145

#SPJ1

3 0
2 years ago
A current of 1.53 a flows through a 63.5 resistor for 6.4 min. How much heat was generated by the resistor
Ira Lisetskai [31]
I am not sure exactly maybe u should ask a friend
8 0
4 years ago
A block slides down a frictionless inclined ramp. If the ramp angle is 17.0° and its length is find the speed of the block as it
SashulF [63]

Answer:

2.4\sqrt{L} where L is the length of the ramp

Explanation:

Let L (m) be the length of the ramp, and g = 9.81 m/s2 be the gravitational acceleration acting downward. This g vector can be split into 2 components: parallel and perpendicular to the ramp.

The parallel component would have a magnitude of

gsin\theta = 9.81 sin17^o = 2.87 m/s^2

We can use the following equation of motion to find out the final velocity of the book after sliding L m:

v^2 - v_0^2 = 2a\Delta s

where v m/s is the final velocity, v_0 = 0m/s is the initial velocity when it starts from rest, a = 2.87 m/s2 is the acceleration, and \Delta s = L is the distance traveled:

v^2 - 0 = 2*2.87*L

v = \sqrt{5.74L} = 2.4\sqrt{L}

6 0
3 years ago
A toy gun uses a spring to project a 5.3 - g soft rubber sphere horizontally. The spring constant is 8.0 N/m, the barrel of the
Vikki [24]

Answer:

v = 1.16 m/s

Explanation:

As per work energy theorem we know that work done by all forces on the sphere is equal to the change in kinetic energy of the sphere

So here we will have

\frac{1}{2}kx^2 - F_f .d = \frac{1}{2}mv^2

here we know that

F_f = 0.032 N

k = 8 N/m

now we have

\frac{1}{2}(8)(0.05^2) - (0.032)(0.15 + 0.05) = \frac{1}{2}(0.0053)v^2

0.01 - 6.4 \times 10^{-3} = 2.65 \times 10^{-3} v^2

v = 1.16 m/s

7 0
4 years ago
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