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romanna [79]
3 years ago
8

A sample of an ideal gas initially occupies a volume of 6 L. The pressure of the sample is then doubled while it is cooled to on

e third its original absolute temperature. After these changes, what volume does the sample occupy?
Physics
1 answer:
Troyanec [42]3 years ago
4 0

Answer:

V₂= 1 L

Explanation:

Given that

Volume occupies V₁= 6 L

Initial pressure = P₁

Initial temperature = T₁

The final pressure =P₂ = 2 P₁

Final volume =V₂

Final temperature = T₁/3

As we know that equation for ideal gas

P V = m R T

P=pressure,  V=volume,   T=temperature

m=mass  ,R=gas constant

Now from mass conservation

m=\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}

\dfrac{P_1V_1}{RT_1}=\dfrac{P_2V_2}{RT_2}

\dfrac{P_1\times 6}{RT_1}=3\times \dfrac{2P_1V_2}{RT_1}

6 = 3 x 2 V₂

V₂= 1 L

So the final volume will be 1 L

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Answer:

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Explanation:

<h2><u>Given</u> :-</h2>

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<h2><u>To Find</u> :-</h2>

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<h2><u>Formula to be used</u> :-</h2>

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<h2><u>Solution</u> :-</h2>

\to\:\:\sf\red{K.E. = \dfrac{1}{2}mv^{2}}

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\to\:\:\sf\purple{100 = v^{2}}

\to\:\:\sf\red{\sqrt{100} = v}

\to\:\:\sf\orange{ 10 = v}

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Answer:

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So, the spring constant of the spring is 49 N/m.

8 0
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