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kicyunya [14]
3 years ago
15

For each of the following cases, indicate whether the net work done is positive, negative, or zero. (a) gravity acting on a fall

ing ball (b) girl accelerating a wagon from rest (c) a skydiver falling at terminal velocity through the air (d) friction acting on a car so that it rolls to a stop.
Physics
1 answer:
irina [24]3 years ago
5 0

Answer:

Explanation:

We to indicate whether work is positive or negative or zero

Note, Work can be define as the produce of force and distance in the direction of the force, work is the dot product of force and displacement

W = F•d

(a) gravity acting on a falling ball

Work done acting on a falling ball is positive, since gravity does work on the ball. And g is positive downward.

Then, Work done by a free falling body is

W = mgh

(b) girl accelerating a wagon from rest

The workdone by a girl accelerating a wagon is positive

Since the wagon is a accelerating, then the velocity is increasing, then, the acceleration is positive

Work done by an accelerating car can be calculated be

W = F×d

Where the force is mass of the car times the positive acceleration

W = m•a•d

(c) a skydiver falling at terminal velocity through the air

The work done is zero since the terminal velocity is constant, so their is no change in velocity, the drag force is equal to the weight of the body and their is no external force acting on the body and the vertical acceleration goes to zero and since no acceleration, the work done is zero

W = m×a×h

W = 0J

But in this case, what is still don't by gravity. Since gravity is not zero.

(d) friction acting on a car so that it rolls to a stop.

The work done by friction is negative. This is due to the fact that the velocity of the car decreases with time and this implies that the car is decelerating, so the acceleration is negative, then,

W = m ×a × d

Since a =-ve

Then, W = —m•a•d

The work done by friction is negative

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Bad White [126]

Answer:

a. 2865 km

Explanation:

Eratosthenes observed that the sun's rays formed a vertical angle of 7º 12 ’. Which confirmed that the Earth was not flat, assuming that it had a spherical shape, using the distance between Alexandria and Siena and the measure of the angle of inclination of the solar rays in Alexandria, calculated the circumference of the Earth.

The calculation was made with a simple rule of three:

angle of inclination of the solar rays——————- distance

               360º                                   ————- Planet circumference

C=\frac{distance*360^\circ}{angle}\\\\C=\frac{500km*360^\circ}{10^\circ}=18000km

And since we know that:

C=2\pi R\\\\R=\frac{C}{2\pi}\\\\R=\frac{18000km}{2\pi}=2865km

6 0
3 years ago
A 19.3 kg dog is running northward at 2.98 m/s , while a 6.26 kg cat is running eastward at 3.64 m/s . Their 78.7 kg owner has t
m_a_m_a [10]

Answer:

v = 0.78 m/sec at 21.61° towards the east of north

Explanation:

Given a 19.3 kg dog is running northward at 2.98 m/s , while a 6.26 kg cat is running eastward at 3.64 m/s and the mass of the owner is 78.7 kg.

Given m(dog) = 19.3 kg and m(cat) = 6.26 kg

v(dog) = 2.98\vec{j} m/sec

v(cat) =  3.64\vec{i} m/sec

Given the \vec{P}(owner)=\vec{P}(dog)+\vec{P}(cat)

Let the velocity of the owner be \vec{v}

We know that \vec{P}=m\vec{v}

m(owner)\times \vec{v}=m(dog)\times \vec{v(dog)}+m(cat)\times \vec{v(cat)}

78.7\times \vec{v}=19.3\times 2.98\vec{j}+6.26\times 3.64\vec{i}

\vec{v}=\frac{1}{78.7}(57.5\vec{j}+22.78\vec{i})

v=\sqrt{(\frac{57.5}{78.7})^2+(\frac{22.78}{78.7})^2  }

v=0.78 m/sec

for direction

Tan(α)=\frac{component of x}{component of y}

where α is the angle toward east of north.

Tan(α)=\frac{22.78}{57.5}

α=21.61°

3 0
3 years ago
Somewhere in the vast flat tundra of planet Tehar, a projectile is launched from the ground at an angle of 60 degrees. It reache
Nina [5.8K]

Answer:

R = 0.0503 m

Explanation:

This is a projectile launching exercise, to find the range we can use the equation

       R = v₀² sin 2θ / g

How we know the maximum height

      v_{f}² =v_{oy}² - 2 g y

      v_{f}= 0

      v_{oy} = √ 2 g y

      v_{oy} = √ 2 9.8 / 15

      v_{oy} = 1.14 m / s

Let's use trigonometry to find the speed

    sin θ = v_{oy} / vo

    vo = v_{oy} / sin θ

    vo = 1.14 / sin 60

    vo = 1.32 m / s

We calculate the range with the first equation

     R = 1.32² sin(2 60) / 30

    R = 0.0503 m

3 0
3 years ago
3. In a physics lab, 0.500-kg cart (Cart A) moving rightward with a speed of 100 m/s collides with a 1.50-kg cart (Cart B) movin
Alex787 [66]

Answer:

The speed of the two carts after the collision is 10 m/s.

Explanation:

Hi there!

The momentum of the system Cart A - Cart B is conserved because there is no external force acting on the system at the instant of the collision. Then, the momentum of the system before the collision will be equal to the momentum of the system after the collision. The momentum of the system is calculated as the sum of momenta of cart A and cart B:

initial momentum = mA · vA1 + mB · vB1

final momentum = (mA + mB) · vAB2

Where:

mA = mass of cart A = 0.500 kg

vA1 = velocity of cart A before the collision = 100 m/s

mB = mass of cart B = 1.50 kg.

vB1 = velocity of cart B before the collision = - 20 m/s

vAB2 = velocity of the carts that move as a single object = unknown.

(notice that we have considered leftward as negative direction)

Since the momentum of system remains constant:

initial momentum = final momentum

mA · vA1 + mB · vB1 = (mA + mB) · vAB2

Solving for vAB2:

(mA · vA1 + mB · vB1) / (mA + mB) = vAB2

(0.500 kg · 100 m/s - 1.50 kg · 20 m/s) / (0.500 kg + 1.50 kg) = vAB2

vAB2 = 10 m/s

The speed of the two carts after the collision is 10 m/s.

6 0
3 years ago
If Jupiter were 10 times more massive, it would generate nuclear fusion in its core and be a star instead of a planet. If Jupite
OverLord2011 [107]

Answer:

False

Explanation:

Let me put it in numbers. Jupiter has mass of 1.898x10^27Kg, make it 10 times as much and it becomes 1.898x10^28 Kg.

TRAPPIST-1, smallest star ever found has Mass of 1.77x10^29Kg, that is around 93 times larger than the mass of Jupiter.

Clearly 10 times as much is not enough to generate fusion reaction and become a star, in theory Jupiter must be at least 85 times larger than it's current mass to be able to generate fusion reaction and become a star.

So i think we can conclude that if Jupiter were to have 10 times of its own mass, it would not become a star, therefore the given statement is False.

5 0
3 years ago
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